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WITCHER [35]
3 years ago
7

A priority encoder circuit has four inputs,X3-0. The circuit has three outputs: Z,Y1-0. If any of X3-0is 1, then Zis 1, and Y re

presentsthe2-bit binary number whose value equals the index of the highest X which is on. For example, if X2=1 and X3=0, then the output are z=1, y1=1 and y0=0. if all input are 0, z=0 and y1 and y0 are dont-cares.
List in decimal form the minterm and dont-cares minterms of each outputs.

Engineering
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

Detailed solution is given below:

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Airbags will deploy in a head on collision but not in a collision that occurs from angle
Aneli [31]

Answer:  

Airbags will deploy in almost any angle.

Explanation:

Cars have sensors around them, so when the car gets hit, the sensors detect a crash and deploy the airbags to keep you safe.

8 0
3 years ago
Anything you want to do in Hootsuite can be found in the ________, with the main workspace in the _________?
Thepotemich [5.8K]

Answer:

Anything you want to do in Hootsuite can be found in the ___ Sidebar_____, with the main workspace in the ___center______

Sidebar; center

Explanation:

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5 0
3 years ago
A site is compacted in the field, and the dry unit weight of the compacted soil (in the field) is determined to be 18 kN/m3. Det
suter [353]

Answer:

the relative compaction is 105.88 %

Explanation:

Given;

dry unit weight of field compaction, W_d_{(field)} = 18 kN/m³

maximum dry unit weight measured, W_d_{(max)} = 17 kN/m³

Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured

Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

RC = \frac{W_d_{(field)}}{W_d_{(max)}}

substitute the given values;

RC = \frac{18}{17} = 1.0588

RC (%) = 105.88 %

Therefore, the relative compaction is 105.88 %

6 0
4 years ago
How much work is required to move an electron from the positive terminal to the negative terminal of a 12 V battery? (Knight 21.
Ray Of Light [21]

Answer:

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

W = -4μJ

Explanation:

Work required to move the charge

W = qΔV

initial point V₁ = 150V

Final point V₂ = -50V

W = q(V₂ -V₁)

= 20 × 10⁹(-50 - 150)

W = -4μJ

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

6 0
3 years ago
Basic concepts surrounding electrical circuitry?​
Elanso [62]
Hopefully that helps you out and is this for history or science?

3 0
3 years ago
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