Answer:
1750 Joules.
Explanation:
Work done = force * distance
= 7 * 250
= 1750 Joules.
The fixed the the lever pivots around is called the fulcrum
I believe the correct answer is expansion.
By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
Answer:
total stretch of the double-length spring will be 20 cm
Explanation:
given data
length x1 = 10 cm
mass = 1 kg
mass = double = 2 kg
to find out
the total stretch of the double-length spring will be
solution
we can say here spring constant is
k = mg ............1
k is spring constant and m is mass and g is acceleration due to gravity
so for in 1st case and 2nd case with 1 kg mass and 2 kg mass
kx1 = mg .........................2
and
kx2 = 2mg ........................3
x is length
so from equation 2 and 3
![\frac{kx1}{kx2}= \frac{1mg}{2mg}](https://tex.z-dn.net/?f=%5Cfrac%7Bkx1%7D%7Bkx2%7D%3D%20%5Cfrac%7B1mg%7D%7B2mg%7D)
![\frac{x1}{x2} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx1%7D%7Bx2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![\frac{10}{x2} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7Bx2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
x2 = 20
so total stretch of the double-length spring will be 20 cm