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liraira [26]
3 years ago
9

HELP PLEASE! What is the slope of the line shown?

Mathematics
1 answer:
Alja [10]3 years ago
7 0

Answer:

A. -4/11

Step-by-step explanation:

Slope formula: \frac{y^2 - y^1}{x^2 - x^1 }

Using the two points substitute the coordinates into this formula

6-2 = 4

4 - 7 = -11

Put 4 over -11 because it is the y value

-\frac{4}{11}

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Enter the x-coordinate of the solution to this system of equations
Kitty [74]

Answer:

equation 2into minus 3 into equation 1

8x+ 3y= -28

-3x-3y=18

----------------

5x=10

x =2

put value of y in equation 2

8 into 2+3y=-28

16+3y= -28

3y= -28+16

3y= -12

y= -4

5 0
2 years ago
Combine the following sets of terms.
DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

=(3x2+−x2)+(−7x+−3x)+(9)

=2x2+−10x+9

Answer :)

=2x2−10x+9


HOPE THIS HELPS

3 0
3 years ago
Please help me with homework will give brainliest
slavikrds [6]

Answer:

A

Step-by-step explanation:

We see that there are 3 in step 2 which means that the only possible answer is A

7 0
3 years ago
Read 2 more answers
an oil spreads 25 square meters every 10 minutes. how much area will the oil spill cover after 1 hour?
professor190 [17]
You know that every 10 minutes the oil moves 25 meters so and in 1 hour there are 60 minutes the equation is 60/10(25) and then you solve

The answer is 150 meters squared
3 0
3 years ago
A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.
steposvetlana [31]
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term. 
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression

7 0
3 years ago
Read 2 more answers
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