1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WARRIOR [948]
3 years ago
14

PLSSS HELP I WILL GIVE U BRAINLIEST annabelle and jose are building a complete circuit for their science inquiry in class they w

ant the lightbulb to turn on and off so they install a switch the light switch can be used to open and close their circuit Given the information above, which statement below must be true about using a switch in a circuit?
A. The switch must use a conductor such as rubber to open the circuit and light the bulb.
B. The switch must use an insulator such as rubber to close the circuit and light the bulb.
C. The switch must use an insulator such as copper to open the circuit and light the bulb.
D. The switch must use a conductor such as copper to close the circuit and light the bulb.
Physics
2 answers:
AlekseyPX3 years ago
8 0

Answer:the answers is D

Explanation:

all the others answers choices are incorrect

Agata [3.3K]3 years ago
6 0

Answer:

i think its C hope this is rhight have a good day

Explanation:

You might be interested in
Explain why the sound produced by every vibrating body cannot be heard by us ?​
VMariaS [17]

Answer:

The human ear is not sensitive to every frequency of sound, rather, our hearing range is from 20Hz to 20,000Hz. This means sound frequencies outside this range are not audible to the human ear, which is why not every sound produced is heard. This is quite a blessing because if we could hear every vibrating body, then our ears would never stop listening: we won't be able to distinguish 'important sounds' from unimportant ones, rendering our ears effectively useless. Perhaps this is why we have a hearing range in the first place: sounds of our friends and our foes lie in 20Hz-20kHz range.

5 0
3 years ago
A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h
Butoxors [25]

Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is m_1=1.6\times 10^4 kg

speed of bus towards North v_1=15.2 km/h\approx 4.22\ m/s

mass of bus travelling in South direction is m_2=1.578\times 10^4 kg

speed of bus v_2=12.2 km/h\approx 3.38\ m/s

mass of each Passenger in south moving bus m_0=64.8 kg

Momentum of North moving bus

P_1=m_1\times v_1

P_1=1.6\times 10^4\times 4.22

P_1=6.768\times 10^4 kg-m/s

Momentum with south moving bus

P_2=m_2\times v_2+n\cdot m_0\times v_2

P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38

For total momentum to be towards south

P_2-P_1 should be greater than 0

thus for least value of n

P_2=P_1

(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4

1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4

n=\frac{4243.6686}{64.8}=65.48\approx 66    

5 0
3 years ago
A softball is thrown from the origin of an x-y coordinate system with an initial speed of 18 m/s at an angle of 35∘ above the ho
podryga [215]
<span>What we need to first do is split the ball's velocity into vertical and horizontal components. To do that multiply by the sin or cos depending upon if you're looking for the horizontal or vertical component. If you're uncertain as to which is which, look at the angle in relationship to 45 degrees. If the angle is less than 45 degrees, the larger value will be the horizontal speed, if the angle is greater than 45 degrees, the larger value will be the vertical speed. So let's calculate the velocities sin(35)*18 m/s = 0.573576436 * 18 m/s = 10.32437585 m/s cos(35)*18 m/s = 0.819152044 * 18 m/s = 14.7447368 m/s Since our angle is less than 45 degrees, the higher velocity is our horizontal velocity which is 14.7447368 m/s. To get the x positions for each moment in time, simply multiply the time by the horizontal speed. So 0.50 s * 14.7447368 m/s = 7.372368399 m 1.00 s * 14.7447368 m/s = 14.7447368 m 1.50 s * 14.7447368 m/s = 22.1171052 m 2.00 s * 14.7447368 m/s = 29.48947359 m Rounding the results to 1 decimal place gives 0.50 s = 7.4 m 1.00 s = 14.7 m 1.50 s = 22.1 m 2.00 s = 29.5 m</span>
6 0
4 years ago
Semi-conductors are materials that
Svetach [21]
Good morning, Jesusperez7!

Semi-conductors are materials that have insulator and conductor properties. 

Thank you for choosing Brainly for your tutoring site, and I hope you enjoy your experience here!


6 0
3 years ago
A car enters a horizontal, curved roadbed of radius 50 m. the coefficient of static friction between the tires and the roadbed i
UkoKoshka [18]
Previous results tell us the speed (v) is given in terms of the coefficient of friction (k) and the radius of the curve (r) as
  v = √(kgr)
  v = √(0.20·9.8 m/s²·50 m)
  = 7√2 m/s ≈ 9.90 m/s
6 0
3 years ago
Read 2 more answers
Other questions:
  • Use the graph to determine the object’s average velocity.
    9·1 answer
  • When the flower below is rotated clockwise 90°, where will the red petal be in the image?
    13·1 answer
  • What is the focal length of the mirror? follow the sign conventions?
    9·1 answer
  • Light of wavelength 600 nm passes though two slits separated by 0.25 mm and is observed on a screen 1.4 m behind the slits. The
    8·2 answers
  • When a highly coherent beam of light is directed against a very fine wire, the shadow formed behind it is not just that of a sin
    13·2 answers
  • A converging lens has a focal length of 19.0 cm. Locate the images for the following object distances. A) 41 cm B) 14cm
    14·1 answer
  • When the Earth is positioned between the Moon and the Sun the following are possible:
    15·1 answer
  • In the video, light passing through two slits creates a pattern of bright and dark fringes on a screen. The bright fringes resul
    9·1 answer
  • 2. If the ball has a velocity of 2.3 m/s, how long does it take it to go 1.1 m?<br> s
    5·1 answer
  • Someone help me is physics
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!