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geniusboy [140]
3 years ago
12

Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.

Which of the following equations could you use to directly solve for the numerical value of t?
Physics
1 answer:
Inga [223]3 years ago
5 0

Answer:

it will take t=\frac{\omega -\omega _0}{\alpha } to reach its final rotating speed

Explanation:

Let initially the turntable is at rest

So its initial angular velocity will be \omega _0=0rad/sec

Let the turn table is rotating with an angular acceleration \alpha

According to first equation of motion

We know that \omega =\omega _0+\alpha t , here \omega

So t=\frac{\omega -\omega _0}{\alpha }

So it will take t=\frac{\omega -\omega _0}{\alpha } to reach its final rotating speed

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SIZIF [17.4K]

The correct symbol is 4He. You may also encounter it displayed as helium-4, He-4.

5 0
3 years ago
A 259-kV power transmission line carrying 429 A is hung from grounded metal towers by ceramic insulators, each having a 0.71×109
ella [17]

Answer:

The resistance is 7.47\times10^{6}\ \Omega.

Explanation:

Given that,

Power = 259 kV

Current = 429 A

Resistance R=0.71\times10^{9}\ Omega

We need to calculate the current in each insulator

Using formula of current

I=\dfrac{P}{R}

Put the value into the formula

I=\dfrac{259\times10^{3}}{0.71\times10^{9}}

I=3.64\times10^{-4}\ A

So all 95 insulators are in parallel

We need to calculate the resistance

Using formula of resistance

\dfrac{1}{R}=\sum_{i=1}^{95}\dfrac{1}{R_{i}}

Put the value into the formula

\dfrac{1}{R}=\dfrac{95}{0.71\times10^{9}}

\dfrac{1}{R}=1.338\times10^{-7}

R=\dfrac{1}{1.338\times10^{-7}}

R=7473841.5=7.47\times10^{6}\ \Omega

Hence, The resistance is 7.47\times10^{6}\ \Omega.

8 0
4 years ago
PLZ HELP ME GUYS!!!! Using appropriate terminology, contrast transverse and longitudinal waves. Hint: How are they different? Yo
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<h3>Longitudinal Waves:</h3>
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4 years ago
A 60kg block is at rest on a ramp inclined at 35 degrees.
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Answer:

Explanation:

(a)Gravitational Force is W=mg

Frictional force is f

Normal force is N

(b)Since the block is in Equilibrium therefore from diagram we can see that  

f=mg\sin \theta

f=60\times 9.8\times \sin 35

f=337.26 N

(c)Magnitude of Normal Force

N=mg\cos \theta =481.66 N

(d)friction is also given by

f=\mu mg\cos \theta

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\mu =0.7  

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What is light intensity? ​
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