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Anna007 [38]
2 years ago
13

Joanna wants to determine the speed of sound in xenon. When she plays a tone with a frequency of 440 Hz, the resulting sound wav

e has a wavelength of 40.4 cm.
a 1090 m/s
b 178 m/s
c 92 m/s
d 343 m/s
Physics
1 answer:
iVinArrow [24]2 years ago
7 0

The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

<h3 /><h3>What is speed?</h3>

Speed can be defined as the ratio of the total distance traveled by a body to the total time taken.

To calculate the speed of the sound in the xenon, we use the formula below.

Formula:

  • v = λf............. Equation 1

Where:

  • v = Speed of the sound in xenon
  • f = Frequency
  • λ = Wavelength.

From the question,

Given:

  • f = 440 Hz
  • λ = 40.4 cm = 0.404 m

Substitute the values above into equation 1

  • v = 440(0.404)
  • v = 177.76 m/s.
  • v ≈ 178 m/s

Hence, The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

Learn more about speed here: brainly.com/question/4931057

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3 years ago
An object will experience a Change in motion if the forces are__________
anastassius [24]

Answer:

According to Newton's first law of motion, an object will experience a change in motion if the forces are unbalanced.

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3 years ago
A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are
slava [35]

Answer:

The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

Explanation:

Given that,

Mass m = 1.81\times10^{-3}\ kg

Velocity v = (3.00\times10^{4}\ m/s)j

Charge q = 1.22\times10^{-8}\ C

Magnetic field B= (1.63\hat{i}+0.980\hat{j})\ T

We need to calculate the acceleration of the particle

Formula of the acceleration is defined as

F = ma=q(v\times B)

a =\dfrac{q(v\times B)}{m}

We need to calculate the value of v\times B

v\times B=(3.00\times10^{4}\ m/s)j\times(1.63\hat{i}+0.980\hat{j})

v\times B=4.89\times10^{4}

Now, put the all values into the acceleration 's formula

a =\dfrac{1.22\times10^{-8}\times(-4.89\times10^{4}\hat{k})}{1.81\times10^{-3}}

a= -0.3296\ \hat{k}\ m/s^2

Negative sign shows the opposite direction.

Hence, The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

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3 years ago
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Describe the difference between balanced forces and action/reaction forces
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3 years ago
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Two charged particles are located on the x axis. The first is a charge 1Q at x 5 2a. The second is an unknown charge located at
sergejj [24]

Answer:

Q_2 = +/- 295.75*Q

Explanation:

Given:

- The charge of the first particle Q_1 = +Q

- The second charge = Q_2

- The position of first charge x_1 = 2a

- The position of the second charge x_2 = 13a

- The net Electric Field produced at origin is E_net = 2kQ / a^2

Find:

Explain how many values are possible for the unknown charge and find the possible values.

Solution:

- The Electric Field due to a charge is given by:

                               E = k*Q / r^2

Where, k: Coulomb's Constant

            Q: The charge of particle

            r: The distance from source

- The Electric Field due to charge 1:

                               E_1 = k*Q_1 / r^2

                               E_1 = k*Q / (2*a)^2

                               E_1 = k*Q / 4*a^2

- The Electric Field due to charge 2:

                               E_2 = k*Q_2 / r^2

                               E_2 = k*Q_2 / (13*a)^2

                               E_2 = +/- k*Q_2 / 169*a^2

- The two possible values of charge Q_2 can either be + or -. The Net Electric Field can be given as:

                               E_net = E_1 + E_2

                               2kQ / a^2 = k*Q_1 / 4*a^2 +/- k*Q_2 / 169*a^2

- The two equations are as follows:

        1:                   2kQ / a^2 = k*Q / 4*a^2 + k*Q_2 / 169*a^2

                               2Q = Q / 4 + Q_2 / 169

                               Q_2 = 295.75*Q

        2:                    2kQ / a^2 = k*Q / 4*a^2 - k*Q_2 / 169*a^2

                               2Q = Q / 4 - Q_2 / 169

                               Q_2 = -295.75*Q

- The two possible values corresponds to positive and negative charge Q_2.

7 0
2 years ago
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