83 km/h * 2.5 hours (3:30 - 1:00) = 207.5 km
207.5 km - 15 km = 192.5 km
Explanation:
I will do two of each as examples.
Boyle's law says that at constant temperature, the product of the initial pressure and volume equals the product of the final pressure and volume.
1. P₁ V₁ = P₂ V₂
(1.5 atm) (10.0 L) = (0.75 atm) V
V = 20.0 L
2. P₁ V₁ = P₂ V₂
(100.0 kPa) (500.0 mL) = P (1,000.0 mL)
P = 50.0 kPa
Charles' law says that at constant pressure, the quotient of the initial volume and temperature equals the quotient of the final volume and temperature.
6. V₁ / T₁ = V₂ / T₂
(10.0 L) / (1500 K) = V / (750 K)
V = 5.0 L
7. V₁ / T₁ = V₂ / T₂
(500.0 mL) / (100 K) = (1000.0 mL) / T
T = 200 K
its important so we can learn things about the species
Answer:
a) X = 17.64 m
b) X = 17.64 + 4∆t^2 + 16.8∆t
c) Velocity = lim(∆t→0)〖∆X/∆t〗 = 16.8 m/s
Explanation:
a) The position at t = 2.10s is:
X = 4t^2
X = 4(2.10)^2
X = 17.64 m
b) The position at t = 2.10 + ∆t s will be:
X = 4(2.10 + ∆t)^2
X = 17.64 + 4∆t^2 + 16.8∆t m
c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,
∆X= 4∆t^2 + 16.8∆t
Divide by ∆t on both sides:
∆X/∆t = 4∆t + 16.8
Taking the limit as ∆t approaches to zero we get:
Velocity =lim(∆t→0)〖∆X/∆t〗 = 4(0) + 16.8
Velocity = 16.8 m/s
