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3 years ago

11

in the early months of some year once I added 0.5 million new accounts every day at this rate how many days would be needed to a

dd 30 million new accounts

1 answer:

blagie [28]3 years ago

7 0

It would take 60 days to add 30 million new accounts

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Solve for variable its in pre algebra

Natalka [10]

Answer:

7

Step-by-step explanation:

7

7 0

2 years ago

The image shows three tennis balls enclosed in a cylindrical can. Choose all that are correct. The volume of a single tennis bal

Fynjy0 [20]

Answer:

The volume of a single tennis ball is $14.14\ in^{3}$

The volume of three tennis balls is $42.42\ in^{3}$

Step-by-step explanation:

Step 1

Find the volume of a single tennis ball

we know that

The volume of a sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

where r is the radius of the sphere

In this problem

$r=3/2=1.5\ in$

substitute

$V=\frac{4}{3}\pi (1.5)^{3}$

$V=14.14\ in^{3}$

Step 2

Find the volume of the can

we know that

the volume of the cylinder is equal to

$V=\pi r^{2} h$

where r is the radius of the cylinder

h is the height of the cylinder

in this problem we have

$r=3/2=1.5\ in$

$h=8.4\ in$

substitute

$V=\pi (1.5)^{2}(8.4)$

$V=59.38\ in^{3}$

Statement

<u>case A)</u> The volume of a single tennis ball is $14.14\ in^{3}$

The statement is true

See the procedure in Step 1

<u>case B)</u> The volume of the can is $56.55\ in^{3}$

The statement is false

The volume of the can is $59.38\ in^{3}$ --> see the procedure Step 2

<u>case C)</u> The empty space inside the can is $14.13\ in^{3}$

The statement is false

To find the empty space subtract the volume of three tennis ball from the volume of the can

$59.38\ in^{3}-3*14.14\ in^{3}=16.96\ in^{3}$

<u>case D)</u> The volume of three tennis balls is $42.42\ in^{3}$

The statement is true

To find the volume of three tennis balls multiply the volume of a single tennis ball by three

$14.14*3=42.42\ in^{3}$

8 0

3 years ago

Find the solutions of the quadratic equation -9c² +2 +3 = 0.

Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here, a = -9, b = 2 and c =3

Put the values,

$c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69$

So, the solution are -0.47 and 0.69.

8 0

2 years ago

3|3t+1|=2|6t+3| Need hep

mars1129 [50]

Answer:

your answer would be t=-1 or t=1

Step-by-step explanation:

-(2t-3) = 3t-2

Multiply

-2t+3 = 3t-2

Rearrange and Add up

-5t = -5

Divide both sides by 5

-t = -1

Multiply both sides by (-1)

t = 1

Which is the solution for the Negative Case

Solve the Positive Case

(2t-3) = 3t-2

Rearrange and Add up

-t = 1

Multiply both sides by (-1)

t = -1

have a great day!

4 0

3 years ago

Need a correct answer please

zloy xaker [14]

Answer x=14 y=1

Step-by-step explanation:

3 0

2 years ago