***elements become less electropositive and more electronegative in their properties...
the answer is car battery
Ep = mgh
= (35)(9.8)(3.5)
= 1200.5 J
Ek = (1/2)(mv^2)
= (0.5)(35)(5^2)
= 437.5 J
Is there a p,if of the question?
Answer:
spacing is 0.8307 mm
Explanation:
given data
wavelength = 500 nm
interference fringes N = 1.5 mm
wavelength = 640 nm
to find out
spacing between the fringes
solution
we know bright fringe spacing in double slit is express as
w × sinθ = N × wavelength
so angle is
sinθ = N × wavelength / w
and spacing is express as
spacing = d sinθ
and that is = N × (d/w) × wavelength
so
spacing = 1.5 × 360 / 650
so spacing is 0.8307 mm