Walking at a speed of 2.1 m/s, in the first 2 s John would have walked
(2.1 m/s) (2 s) = 4.2 m
Take this point in time to be the starting point. Then John's distance from the starting line at time <em>t</em> after the first 2 s is
<em>J(t)</em> = 4.2 m + (2.1 m/s) <em>t</em>
while Ryan's position is
<em>R(t)</em> = 100 m - (1.8 m/s) <em>t</em>
where Ryan's velocity is negative because he is moving in the opposite direction.
(b) Solve for the time when they meet. This happens when <em>J(t)</em> = <em>R(t)</em> :
4.2 m + (2.1 m/s) <em>t</em> = 100 m - (1.8 m/s) <em>t</em>
(2.1 m/s) <em>t</em> + (1.8 m/s) <em>t</em> = 100 m - 4.2 m
(3.9 m/s) <em>t</em> = 95.8 m
<em>t</em> = (95.8 m) / (3.9 m/s) ≈ 24.6 s
(a) Evaluate either <em>J(t)</em> or <em>R(t)</em> at the time from part (b).
<em>J</em> (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m
A line that is falling towards the x axis represents an object that is negatively accelerating, or slowing down. When the line hits the x axis, the object has stopped moving. If the graph continues below the x axis, the object has changed direction and is moving backwards at increasing velocity.
Hey there,
Your question states: <span>Debbie places two shopping carts in a cart corral. She pushes the first cart, which then pushes a second cart. What force is being exerted?
based by looking at this statement above about Debbie, I understand that she (pushed) Cart (A) first. And then, she exerted (Cart B) next. From the option's that are listed above, I only see two. But from my own words, not from the only (two) options above, I see that (Debbie first exerts the second cart on to the first cart). This reason would be because the first cart is already in the corral. So then she would put the second one in there, this would mean that the second one would push the other one in there. Which means that the velocity would also be in half.
I hope you grabbed my answer in there.
~Jurgen</span>
Answer:
The volume of water displaced the same as the volume of the block.
Explanation:
With respect to the principle of floatation, when an object floats in a fluid; its weight is the same as the volume of the fluid displaced.
The volume of the block relates to is dimension and size which can be compared with the volume of the fluid displaced. When the block is floats in water, it would displace a reasonable volume of water. Thus, it would be expected that the volume of water displaced by the block is equal to the volume of the block.