1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
12

A steel casting weighing 2 kg has an initial temperature of 500°c; 25 kg of water initially at 25°c is contained in a perfectly

insulated steel tank weighing 5 kg. the casting is immersed in the water and the system is allowed to come to equilibrium. what is its final temperature? ignore the effects of expansion or contraction, and assume constant specific heats of 4.18 kj⋅kg−1⋅°c−1 for water and 0.50 kj⋅kg−1⋅°c−1 for steel.
Physics
2 answers:
gayaneshka [121]3 years ago
5 0

Answer:

26.6C

Explanation:

Using an energy balance:

Decrease in internal energy of casting must lead to an increase in internal energy of the tank and water, assuming that no heat flows out of the tank - perfectly insulated.

m_{casting}*C_{p,casting}*(T_{casting} - T_{final})= m_{water}*C_{p,water}*(T_{final} - T_{water}) + m_{tank}*C_{p,tank}*(T_{final} - T_{tank})

2*0.5*(500 - T_{final})= 70*4.18*(T_{final} - 25) + 5*0.5*(T_{final} - 25)\\\\(1+2.5+292.6)*T_{final} = 500+7315+62.5\\\\T_{final} = 26.6C

SCORPION-xisa [38]3 years ago
3 0
<span> Plan: Use Q = m · c · ΔT three times. Hot casting cools ΔT_hot = 500°C - Tf. Cold water and steel tank heat ΔT_cold = Tf - 25°C. Set Q from hot casting cooling = Q from cold tank heating.
here
m_cast · c_steel · ΔT_hot = (m_tank · c_steel + m_water · c_water) · ΔT_cold

m_cast · c_steel · (500°C - Tf) = (m_tank · c_steel + m_water · c_water) · (Tf - 25°C)

2.5 kg · 0.50 kJ/(kg K°) · (500°C - Tf) = (5 kg· 0.50 kJ/(kg K°) + 40 kg· 4.18 kJ/(kg K°)) · (Tf - 25°C)

Solve for Tf, remember that K° = C° (i.e. for ΔT's) </span>
You might be interested in
Superconductors have no measurable resistance. true or false?
trapecia [35]
True, they have zero electrical resistance.
7 0
3 years ago
A closely wound search coil has an area of 3.13 cm2, 135 turns, and a resistance of 61.1 Ω. It is connected to a charge-measurin
erastovalidia [21]

Answer:

Explanation:

Let the magnitude of magnetic field be B .

flux passing through the coil's  = area of coil x field x no of turns

Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .

emf induced = dΦ / dt , Φ is magnetic flux.

current i = dΦ /dt x 1/R

charge through the coil = ∫ i dt

= ∫   dΦ /dt x 1/R dt

= 1 / R ∫ dΦ

= Φ / R

Total resistance R = 61.1 + 44.4 = 105.5 ohm .

3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5

B = 3.44 x 10⁻⁵ x 105.5  / 422.55 x 10⁻⁴

= .86 x 10⁻¹

= .086 T .

8 0
3 years ago
g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosyn
krok68 [10]

Answer:

r = 4.21 10⁷ m

Explanation:

Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining

            T² = (\frac{4\pi }{G M_s} ) r³             (1)

           

in this case the period of the season is

            T₁ = 93 min (60 s / 1 min) = 5580 s

            r₁ = 410 + 6370 = 6780 km

            r₁ = 6.780 10⁶ m

for the satellite

           T₂ = 24 h (3600 s / 1h) = 86 400 s

if we substitute in equation 1

            T² = K r³

            K = T₁²/r₁³

            K = \frac{ 5580^2}{ (6.780 10^6)^2}

            K = 9.99 10⁻¹⁴ s² / m³

we can replace the satellite values

            r³ = T² / K

            r³ = 86400² / 9.99 10⁻¹⁴

            r = ∛(7.4724 10²²)

            r = 4.21 10⁷ m

this distance is from the center of the earth

7 0
3 years ago
A block is projected up a frictionless inclined plane with initial speed v0 = 1.72 m/s. The angle of incline is θ = 44.8°. (a) H
Snowcat [4.5K]

Explanation:

Given

initial velocity(v_0)=1.72 m/s

\theta =44.8{\circ}

using v^2-u^2=2as

Where v=final velocity (Here v=0)

u=initial velocity(1.72 m/s)

a=acceleration   (gsin\theta )

s=distance traveled

0-(1.72)^2=2(-9.81\times sin(44.8))s

s=0.214 m

(b)time taken to travel 0.214 m

v=u+at

0=1.72-gsin(44.8)\times t

t=\frac{1.72}{9.8\times sin(44.8)}

t=0.249 s

(c)Speed of the block at bottom

v^2-u^2=2as

Here u=0 as it started coming downward

v^2=2\times gsin(44.8)\times 0.214

v=\sqrt{2.985}

v=1.72 m/s

3 0
3 years ago
Seasons are more noticeable in places that are____from to the equator
Liula [17]
1. farther
2. true

the equator is a weirdo
4 0
3 years ago
Other questions:
  • A car travels from point a to point b, moving in the same direction but with a non-constant speed. the first half of the distanc
    15·2 answers
  • During its final days as a red giant, the Sun will reach a peak luminosity of about 3000LSun. Earth will therefore absorb about
    14·1 answer
  • Rounded to the nearest whole number, how many protons are in an atom of krypton?
    6·2 answers
  • Which section (A or B) of the roller coaster shows positive acceleration?
    14·2 answers
  • Explain why gases make better thermal insulators than solids or liquids.​
    10·2 answers
  • Three blocks of metal at the same temperature are placed on a hot stove. Their specific heat capacities are listed below. Rank t
    6·1 answer
  • You can make a solute dissolve more quickly in a solvent by
    9·1 answer
  • I need help pleaseee
    9·1 answer
  • If time is tripled and work remains the same the power will.​
    12·1 answer
  • You have two rocks made of the same material that are at the same
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!