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Bingel [31]
3 years ago
8

From left to right across a period in the periodic table, elements become less ___________ and more ______________ in their prop

erties.
Physics
2 answers:
leonid [27]3 years ago
7 0
***elements become less electropositive and more electronegative in their properties...
Paul [167]3 years ago
6 0

Explanation:

When we move across a period in the periodic table then there occurs an increase in the electronegativity of the elements because of decrease in their atomic size.

Electronegativity is the ability of an atom to attract electrons towards itself.

This also means that on moving from left to right in a periodic table elements become less electropositive in nature.

Therefore, we can conclude that from left to right across a period in the periodic table, elements become less electropositive and more electronegative in their properties.

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A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to turn
lyudmila [28]

A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to reverse your car If you can't do it

Red is typically used to indicate danger or warning, and on traffic lights, it indicates a potential hazard ahead and, as a result, serves as a signal for drivers to stop. If the traffic light turns red while you are already at a junction, you must move swiftly to the opposite side to avoid a potential accident with oncoming traffic.
If the traffic light has turned red as you approach the junction and you are just entering it, you must stop. Unless there is a sign clearly telling you not to turn left at the red light, you may do so. Give way to people and cars coming from other directions when turning.

To learn more about Traffic lights please visit -
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7 0
2 years ago
Read 2 more answers
A 10kg block is Pulled along a horizontal
Leviafan [203]

Answer:

Explanation:

I hate these kinds of problems,  luckily I can't understand how much the kinetic friction is for this ,  the words are all mixed around.  and don't read well.  Maybe this went through a translator program?   My suggestion draw the free body diagram.   so you can see where the forces are, and how they are acting.   getting the free body diagram right.. usually makes these problems pretty straight forward.   just do the steps and you get the answer.

6 0
3 years ago
Read 2 more answers
As your rockets went upwards how would you describe how the energies changed?
chubhunter [2.5K]

As a rocket increases height and slows down, it gains more and more potential energy and loses more and more kinetic energy. Potential energy is store energy (usually determined by height), and kinetic energy increases as speed increases.

4 0
3 years ago
Can someone see if it's right? thank you. ​
bearhunter [10]

Answer:

it's right you did a great job

8 0
2 years ago
The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh
Aliun [14]

Answer:

The value is      A   = 39315 \  m^2

Explanation:

From the question we are told that

    The velocity which the rover is suppose to land with is  v  =  1 \ m/s

    The  mass of the rover and the parachute is  m  =  2270 \ kg

     The  drag coefficient is  C__{D}}  =  0.5

      The atmospheric density of Earth  is  \rho =  1.2 \  kg/m^3

     The acceleration due to gravity in Mars is  g_m  =  3.689 \  m/s^2

     

Generally the Mars  atmosphere density is mathematically represented as

          \rho_m  =  0.71 *  \rho

=>        \rho_m  =  0.71 *  1.2

=>        \rho_m  = 0.852 \  kg/m^3

Generally the drag force on the rover and the parachute  is mathematically represented as

          F__{D}} =  m  *  g_{m}

=>       F__{D}} =  2270   *  3.689  

=>       F__{D}} =  8374 \ N  

Gnerally this drag force is mathematically represented as

         F__{D}} =   C__{D}} *  A *  \frac{\rho_m * v^2 }{2}

Here A is the frontal area

So  

         A   =  \frac{2 *  F__D }{ C__D}  *  \rho_m  * v^2   }

=>       A   =  \frac{2 * 8374 }{ 0.5 *  0.852    *  1 ^2   }

=>       A   = 39315 \  m^2

8 0
3 years ago
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