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liraira [26]
3 years ago
6

What is convention? (not politically)

Chemistry
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

a way in which something is usually done, especially within a particular area or activity.

Explanation:

Mrac [35]3 years ago
3 0

Answer:

the transfer of heat by the circulation or movement of the heated parts of a liquid or gas. Meteorology. the vertical transport of atmospheric properties, especially upward (distinguished from advection).

Explanation:

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Identify which location in the periodic table you would have the<br> largest atomic radii.
bearhunter [10]

Answer:

left to right across a period when it decreases and when it increases top to bottom in a group,

hope i helped

5 0
3 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
3 years ago
Label the parts of the atom.<br><br> Which atomic particle determines the identity of the atom?
zavuch27 [327]
A: Electron
B: Neutron
C: Proton
3 0
3 years ago
What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4
Ivenika [448]

Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

Explanation:

Need 4.90L of HCl(aq) solution with pH = 1.5.

Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺

[HCl(36%)] ≅ 12M in HCl

(M·V)concentrate = (M·V)diluted

12M·V(conc) = 0.032M·4.91L

=> V(conc) needed = [(0.032)(4.91)/12]Liters = 0.0130Liters or 130 ml.

Mixing Caution => Add 131 ml of HCl(36%) into a small quantity of water (~500ml) then dilute to the mark.

5 0
3 years ago
Is the sky a solid liquid or gas
s2008m [1.1K]
Gas.
The sky is not solid, not liquid but of gas. It is also called the atmosphere, one of the important spheres on earth that influences the climate –temperature, humidity, precipitation, atmospheric pressure, and the biotic community as a whole. The atmosphere or the sky is composed of many layers and is responsible to protecting the living organisms of the earth against the deadly ultraviolet rays and other strong radiation coming from the sun.



6 0
3 years ago
Read 2 more answers
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