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Lemur [1.5K]
3 years ago
11

Find a numerical value of one trigonometric function of x for cscx=sinxtanx+cosx

Mathematics
2 answers:
ehidna [41]3 years ago
5 0

cscx = sinx tan x + cos x

Using xsx x = 1/sin x and tan x = sin x/cos x

\frac{1}{sin x} = sinx *\frac{sinx }{cos x} + cosx

\frac{1}{sin x} = \frac{sin^2x +cos^2x}{cos x}

\frac{1}{sin x} = \frac{1}{cos x}

Multiplying both sides by cos x

\frac{cos x}{sin x} = 1

cot x =1

Correct option is d .

egoroff_w [7]3 years ago
5 0

Answer: d. cotx=1

Step-by-step explanation: cosecx=sinxtanx+cosx

                             ⇒             cosecx=  sinx×\frac{sinx}{cosx} +cosx

                             ⇒              cosecx=\frac{sin^{2}x  }{cosx} +cosx

                             ⇒          cosecx= \frac{sin^{2}x+cos^{2} x }{cosx}

                             ⇒            cosecx= 1/cosx     (since sin²x+cos²x=1)

                            ⇒             1/sinx=1/cosx

                           ⇒             cosx/sinx=1

                            ⇒             cotx=1

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AlladinOne [14]

ANSWER:

#include <stdio.h>

#define PAYRATE 10 //basic pay rate per hour

#define OVERTIME 15 //in excess of 40 hours a week

int NetPay(int hours);

int main()

{

int userWeeklyHours;

printf("Please enter your total weekly working hours: \n");

scanf("%d", &userWeeklyHours);// get the user weekly hours

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return 0;

}

int NetPay(int hours)// implementing the function to calculate total pay, total taxes, and net pay

{

int firstRate, secondRate, restOfRate, secondAmount, rest, payAfterTax, payedBeforeTax, overHours;

if (hours > 40)

{

overHours = hours - 40;

payedBeforeTax = (40 * PAYRATE) + (overHours * OVERTIME);

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else

payedBeforeTax = hours * PAYRATE;//defining the user first paycheck before taxes

if (payedBeforeTax <= 300)//paying only first rate case

{

firstRate = payedBeforeTax*0.15;

payAfterTax =payedBeforeTax - firstRate;

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else if (payedBeforeTax > 300 && payedBeforeTax <= 450)//paying first and second rate

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Answer:

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Step-by-step explanation:

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6 0
4 years ago
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Scorpion4ik [409]

I realize the double number line in this exercise can be as shown in the attached image, in that case, the table, correctly completed is:

Eggs      Time (hours)

 3                   <u>75</u>

 <u>4</u>                  100

 12                <u>300</u>

Method to complete the table.

First, you must see the double number line (attached image), in this we identify a hen needs 25 hours to lay 1 egg, by this reason, to identify the time required for a certain number of eggs, just multiply the number of eggs by 25 (the number of hours shown on the double number line), then:

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To calculate the number of eggs taking into account the time, you must divide the hours by 25:

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In this way, <u><em>you can check that the answers are 75, 4, and 300 respectively, to complete the table in the correct form</em></u>.

You can review more exercises and test your new knowledge about the double number line at the following link: brainly.com/question/13553589?referrer=searchResults

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My name is Ann [436]

Answer:

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Step-by-step explanation:

The expressions provided are:

(i)\ x+((y\times (z')) +t)\\\\(ii)\ x\times((x+(y'))+z)

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x+((y\times (z')) +t)=x+(yz'+t)

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(ii)

Simplify the second expression with as few symbols as possible:

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                              =x (x+y'+z)

Thus, the simplified expressions are (<em>x</em> + <em>y·</em>z' + <em>t</em>) and <em>x·</em>(<em>x</em> + <em>y</em>' + <em>z</em>) respectively.

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Cloud [144]
It’s 10 that’s the answer
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