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Lemur [1.5K]
3 years ago
11

Find a numerical value of one trigonometric function of x for cscx=sinxtanx+cosx

Mathematics
2 answers:
ehidna [41]3 years ago
5 0

cscx = sinx tan x + cos x

Using xsx x = 1/sin x and tan x = sin x/cos x

\frac{1}{sin x} = sinx *\frac{sinx }{cos x} + cosx

\frac{1}{sin x} = \frac{sin^2x +cos^2x}{cos x}

\frac{1}{sin x} = \frac{1}{cos x}

Multiplying both sides by cos x

\frac{cos x}{sin x} = 1

cot x =1

Correct option is d .

egoroff_w [7]3 years ago
5 0

Answer: d. cotx=1

Step-by-step explanation: cosecx=sinxtanx+cosx

                             ⇒             cosecx=  sinx×\frac{sinx}{cosx} +cosx

                             ⇒              cosecx=\frac{sin^{2}x  }{cosx} +cosx

                             ⇒          cosecx= \frac{sin^{2}x+cos^{2} x }{cosx}

                             ⇒            cosecx= 1/cosx     (since sin²x+cos²x=1)

                            ⇒             1/sinx=1/cosx

                           ⇒             cosx/sinx=1

                            ⇒             cotx=1

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<em>Solve for q.  </em>

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