Answer:
62.17% probability that a randomly selected exam will require more than 15 minutes to grade
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected exam will require more than 15 minutes to grade
This is 1 subtracted by the pvalue of Z when X = 15. So
has a pvalue of 0.3783.
1 - 0.3783 = 0.6217
62.17% probability that a randomly selected exam will require more than 15 minutes to grade
Answer:
A:SPA =CFA by AA
Step-by-step explanation:
Hopefully this helps
Slope(m) = -2 hope this helps
Answer:
P ( 37 < x < 41) = P(-0.5 < Z < 1.5) = 0.6247
Step-by-step explanation:
We know mean u = 38 standard dev. s = 2
We want P ( 37 < x < 41)
so
P( (37 - 38) / 2 < Z) = P(-0.5 < Z)
P( Z < (41 - 38)/2 ) = P( Z < 1.5)
Find P(Z < -0.5) = 0.3085
Find P(Z > 1.5) = 0.0668
so P(-0.5 < Z < 1.5) = 1 - P(Z < -0.5) - P(Z > 1.5)
P(-0.5 < Z < 1.5) = 1 - 0.3085 - 0.0668
P(-0.5 < Z < 1.5) = 0.6247
P ( 37 < x < 41) = P(-0.5 < Z < 1.5) = 0.6247
(2, 8)
Because you cannot divide by 0, which 2 would do to the bottom.