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Lera25 [3.4K]
3 years ago
15

Could I please get some help on this question I don’t understand .

Physics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

12.5 m/s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 8 m

Final velocity (v) at 8 m above the lowest point =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 8)

v² = 0 + 156.8

v² = 156.8

Take the square root of both side

v = √156.8

v = 12.5 m/s

Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.

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Calculate the wavelengths of the first five members of the Lyman series of spectral lines, providing the result in units Angstro
Oduvanchick [21]

Answer:

Explanation:

The formula for hydrogen atomic  spectrum is as follows

energy of photon due to transition from higher orbit n₂ to n₁

E=13.6 (\frac{1}{n_1^2 } - \frac{1}{n_2^2})eV

For layman series n₁ = 1 and n₂ = 2 , 3 , 4 ,   ...   etc

energy of first line

E_1=13.6 (\frac{1}{1^2 } - \frac{1}{2 ^2})

10.2 eV

wavelength of photon = 12375 / 10.2 = 1213.2 A

energy of 2 nd line

E_2=13.6 (\frac{1}{1^2 } - \frac{1}{3 ^2})

= 12.08 eV

wavelength of photon = 12375 / 12.08 = 1024.4 A

energy of third line

E_3=13.6 (\frac{1}{1^2 } - \frac{1}{4 ^2})

12.75 e V

wavelength of photon = 12375 / 12.75 = 970.6 A

energy of fourth line

E_4=13.6 (\frac{1}{1^2 } - \frac{1}{5 ^2})

= 13.056 eV

wavelength of photon = 12375 / 13.05 = 948.3 A

energy of fifth line

E_5=13.6 (\frac{1}{1^2 } - \frac{1}{6 ^2})

13.22 eV

wavelength of photon = 12375 / 13.22 = 936.1 A

7 0
3 years ago
Slow-twitch muscles are needed for what?
Tresset [83]
Slow-twitch muscles<span> help enable long-endurance feats such as distance running, while fast-</span>twitch muscles<span> fatigue faster but are used in powerful bursts of movements like sprinting. Hope that this can help!!!</span>
8 0
2 years ago
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An ideal gas is allowed to expand isothermally from 2.00 l at 5.00 atm in two steps:
Burka [1]

Heat added to the gas = Q = 743 Joules

Work done on the gas = W = -743 Joules

\texttt{ }

<h3>Further explanation</h3>

The Ideal Gas Law that needs to be recalled is:

\large {\boxed {PV = nRT} }

<em>P = Pressure (Pa)</em>

<em>V = Volume (m³)</em>

<em>n = number of moles (moles)</em>

<em>R = Gas Constant (8.314 J/mol K)</em>

<em>T = Absolute Temperature (K)</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

<u>Unknown:</u>

Work done on the gas = W = ?

Heat added to the gas = Q = ?

<u>Solution:</u>

<h3>Step A:</h3>

<em>Ideal gas is allowed to expand isothermally:</em>

P_1V_1 = P_2V_2

5.00 \times 2.00 = 3.00 \times V_2

V_2 = 10 \div 3

V_2 = 3\frac{1}{3} \texttt{ L}

\texttt{ }

<em>Next we will calculate the work done on the gas:</em>

W_A = -P_2(V_2 - V_1)

W_A = -3.00(3\frac{1}{3} - 2.00)

W_A = \boxed{-4 \texttt{ L.atm}}

\texttt{ }

<h3>Step B:</h3>

<em>Using the same method as above:</em>

P_2V_2 = P_3V_3

3.00 \times 3\frac{1}{3} = 2.00 \times V_3

V_3 = 10 \div 2

V_3 = 5 \texttt{ L}

\texttt{ }

<em>Next we will calculate the work done on the gas:</em>

W_B = -P_3(V_3 - V_2)

W_B = -2.00(5 - 3\frac{1}{3})

W_B = \boxed{-3\frac{1}{3} \texttt{ L.atm}}

\texttt{ }

<em>Finally we could calculate the total work done and heat added as follows:</em>

W = W_A + W_B

W = -4 + (-3\frac{1}{3})

W = -7\frac{1}{3} \texttt{ L.atm}

W = -7\frac{1}{3} \times 101.33 \texttt{ J}

\boxed{W \approx -743 \textt{ J}}

\texttt{ }

\Delta U = Q + W

0 = Q + (-743)

\boxed{Q = 743 \texttt{ J}}

\texttt{ }

<h3>Learn more</h3>
  • Minimum Coefficient of Static Friction : brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

5 0
3 years ago
anonymous 4 years ago The turbidity levels of water in four locations are shown in the table below. Which of these conclusions i
Tresset [83]
Hello!

The Correct Answer would 100% be:

Option "C".

"People in location C would complain about foul taste in water".

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
4 0
3 years ago
Read 2 more answers
Please can someone help me im struggling asap ill mark brainlist
juin [17]

Answer:

1. A

2. C

3. A

4. D

5. B

Explanation:

4 0
2 years ago
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