Answer:
The magnitude of the magnetic force this particle experiences is 
.
Explanation:
Given that,
Velocity v= (3i-5j+k) m/s
Magnetic field B=(i+2j-k) T
We need to calculate the value 
We need to calculate the magnitude of the magnetic force this particle experiences
Using formula of magnetic force
Put the value into the formula
Hence, The magnitude of the magnetic force this particle experiences is .
Answer:
The right response will be "450 volts".
Explanation:
The given values are:
R1 = 4.00 cm
R2 = 6.00 cm
q1 = +6.00 nC
q2 = −9.00 nC
As we know,
The potential difference between the two shell's difference will be:
⇒ ![\Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]](https://tex.z-dn.net/?f=%5CDelta%20V%3DK%5B%28%5Cfrac%7Bq1%7D%7BR1%7D%2B%5Cfrac%7Bq2%7D%7BR2%7D%29-%28%5Cfrac%7Bq1%7D%7BR1%7D%20%2B%28%5Cfrac%7Bq2%7D%7BR2%7D%29%29%5D)
![=K[\frac{q1}{R2}-\frac{q1}{R1} ]](https://tex.z-dn.net/?f=%3DK%5B%5Cfrac%7Bq1%7D%7BR2%7D-%5Cfrac%7Bq1%7D%7BR1%7D%20%5D)
On substituting the values, we get
![=(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]](https://tex.z-dn.net/?f=%3D%289%5Ctimes%2010%5E9%29%5B%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.04%7D-%5Cfrac%7B6%5Ctimes%2010%5E%7B-9%7D%7D%7B0.06%7D%5D)
Δ 
Answer:
The angular velocity is slowing down.
Explanation:
- By convention, if a rigid body is rotating clockwise, the angular velocity is negative.
- If the angular acceleration has a positive sign, since the angular acceleration and the angular velocity have opposite signs, this means that the angular velocity is slowing down.
A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction between the box and the surface of the incline is 0.180. the initial speed of the box at the bottom of the incline is 2.20 m/s. how far does the box travel along the incline before coming to rest?
