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Svetradugi [14.3K]

3 years ago

8

bill won 50 lollipops playing the bean bag toss at the country fair. at school he gave three to every student in his math class.

he only has 2 remaining. how many students are in his class?

1 answer:

alukav5142 [94]3 years ago

3 0

Answer:

16 kids

Step-by-step explanation:

50-2=48

48/3=16

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Need help finding the side length, thank you! please try and show work or you can

Tasya [4]

Answer: x=16

Step-by-step explanation:

For this problem, we can set a proportion to find the side length of the smaller rectangle.

$\frac{15}{24}=\frac{10}{x}$ [cross multiply]

$15x=240$ [divide both sides by 15]

x=16

8 0

3 years ago

What is the interquartile range of this data 0 5 10 15 20

timama [110]

The interquartile range (IQR) is 15.

To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1

5 0

3 years ago

The number 40 can be written as the product of a prime factor like 40=2×2×2×5 . Write the number 100 as a product of its prime f

Vladimir79 [104]

Answer

The answer to your question is 2 x 2 x 5 x 5 or 2² 5²

Step-by-step explanation:

Process

1.- To find the prime factors of a number, we must divide the number by prime numbers like 2, 3, 5, 7, 11, etc. starting from the lowest number.

100 2

50 2

25 5

5 5

1

Then 100 = 2 x 2 x 5 x 5 or 2² 5²

5 0

3 years ago

Y=x+1<br> y=x^2-1<br><br> please help i don't understand

ololo11 [35]

ANSWER

The solution is

$(x=1,y=2),(x=2,y=3)$

<u>EXPLANATION</u>

We have

$y=x+1---(1)$

and

$y=x^2-1---(2)$

Let us substitute equation (1) in to equation (2). This gives us,

$x+1=x^2-1(2)$

We rewrite this as a quadratic equation as the highest degree is 2.

$x^2-x-1-1=0$

This implies that

$x^2-x-2=0$

we factor to obtain,

$x^2+x-2x-2=0$

$x(x-1)-2(x-1)=0$

$(x-1)(x-2)=0$

This means,

$(x-1)=0\:\: or\:\:(x-2)=0$

$x=1\:\: or\:\:x=2$

We substitute this values into any of the above equations, preferably equation (1)

When, $x=1$ , $y=1+1=2$

When, $x=2$ , $y=2+1=3$

The solution is

$(1,2),(2,3)$

8 0

4 years ago

Nathaniel is using the quadratic formula to solve 0 = x2 + 5x - 6. His steps are shown below.

jek_recluse [69]

Answer:

x = -6, 1

Step-by-step explanation:

x= $\frac{-5+\sqrt{49} }{2}$ or x= $\frac{-5-\sqrt{49} }{2}$

x= $\frac{-5+7}{2}$ or x= $\frac{-5-7}{2}$

x=2/2 or x=-12/2

x = 1, -6

8 0

3 years ago