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Paladinen [302]
3 years ago
13

A man drives south to work every

Physics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

a space-probe flyby of the planet Neptune involves motion. When you

are resting, your heart moves blood through your veins. And even in inanimate objects, there is continuous motion in the vibrations of atoms and

molecules. Questions about motion are interesting in and of themselves: How long will it take for a space probe to get to Mars? Where will a football

land if it is thrown at a certain angle? But an understanding of motion is also key to understanding other concepts in physics. An understanding of

acceleration, for example, is crucial to the study of force.

Our formal study of physics begins with kinematics which is defined as the study of motion without considering its causes. The word “kinematics”

comes from a Greek term meaning motion and is related to other English words such as “cinema” (movies) and “kinesiology” (the study of human

motion). In one-dimensional kinematics and Two-Dimensional Kinematics we will study only the motion of a football, for example, without worrying

about what forces cause or change its motion. Such considerations come in other chapters. In this chapter, we examine the simplest type of

motion—namely, motion along a straight line, or one-dimensional motion. In Two-Dimensional Kinematics, we apply concepts developed here to

study motion along curved paths (two- and three-dimensional motion); for example,must first be able to describe its position—where it is at any particular time. More precisely, you

need to specify its position relative to a convenient reference frame. Earth is often used as a reference frame, and we often describe the position of

an object as it relates to stationary objects in that reference frame. For example, a rocket launch would be described in terms of the position of the

rocket with respect to the Earth as a whole, while a professor’s position could be described in terms of where she is in relation to the nearby white

board. (See Figure 2.3.) In other cases, we use reference frames that are not stationary but are in motion relative to the Earth. To describe the

position of a person in an airplane, for example, we use the airplane, not the Earth, as the reference frame. (See Figure 2.4.)

Displacement

If an object moves relative to a reference frame (for example, if a professor moves to the right relative to a white board or a passenger moves toward

the rear of an airplane), then the object’s position changes. This change in position is known as displacement. The word “displacement” implies that

an object has moved, or has been displaced.

Displacement

Displacement is the change in position of an object:

Δx = x (2.1) f − x0

,

where Δx is displacement, xf

is the final position, and x0

is the initial position.

In this text the upper case Greek letter Δ (delta) always means “change in” whatever quantity follows it; thus, Δx means change in position.

Always solve for displacement by subtracting initial position x0

from final position xf

.

Note that the SI unit for displacement is the meter (m) (see Physical Quantities and Units), but sometimes kilometers, miles, feet, and other units of

length are used. Keep in mind that when units other than the meter areassenger moves from his seat to the back of the plane. His location relative to the airplane is given by x . The −4.0-m displacement of the passenger

relative to the plane is represented by an arrow toward the rear of the plane. Notice that the arrow representing his displacement is twice as long as the arrow representing the

displacement of the professor (he moves twice as far) in Figure 2.3.

Note that displacement has a direction as well as a magnitude. The professor’s displacement is 2.0 m to the right, and the airline passenger’s

displacement is 4.0 m toward the rear. In one-dimensional motion, direction can be specified with a plus or minus sign. When you begin a problem,

you should select which direction is positive (usually that will be to the right or up, but you are free to select positive as being any direction). The

professor’s initial position is x0 = 1.5 m and her final position is xf = 3.5 m . Thus her displacement is

Δx = x (2.2) f −x0 = 3.5 m − 1.5 m = + 2.0 m.

In this coordinate system, motion to the right is positive, whereas motion to the left is negative. Similarly, the airplane passenger’s initial position is

x0 = 6.0 m and his final position is xf = 2.0 m , so his displacement is

Δx = x (2.3) f −x0 = 2.0 m − 6.0 m = −4.0 m.

His displacement is negative because his motion is toward the rear of the plane, or in the negative x direction in our coordinate system.

Distance

Although displacement is described in terms of direction, distance is not. Distance is defined to be the magnitude or size of displacement between

two positions. Note that the distance between two positions is not the same as the distance traveled between them. Distance traveled is the total

length of the path traveled between two positions. Distance has no direction and, thus, no signal

Explanation: pls brainlist

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A bucket of mass m is hanging from the free end of a rope whose other end is wrapped around a drum (radius R, mass M) that can r
mr Goodwill [35]

Answer:

Explanation:

Let T be the tension .

Applying newton's second law on the downward movement of the bucket

mg - T = ma

On the drum , a torque of TR will be acting which will create an angular acceleration of α in it . If I be the moment of inertia of the drum

TR = Iα

TR = Ia/ R

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Replacing this value of T in the other equation

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mg =  Ia/ R² +ma

a ( I/ R² +m)= mg

a = mg / ( I/ R² +m)

mg - T = ma

mg - ma  = T

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7 0
4 years ago
Can you help me with this paper please I will give you 20 points!
sweet [91]
1) they are attracting because if you look at the arrows they’re all pointing the same way.

2) if the magnet was turned around they would do the opposite and not attract ( this is called repulsion)

3) magnetic pole

4)magnet

5) magnetic force

6) magnetism

Hope this helps
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A 2.0kg rock is thrown straight up into the air with a speed of 30m/s. Ignore air resistance. What is the net force acting on th
bazaltina [42]

Answer:

19.6N

Explanation:

Given parameters:

Mass of rock = 2kg

Speed  = 30m/s

Unknown:

Net force on the rock  = ?

Solution:

The net force acting on this rock is a function of the acceleration due to gravity acting upon it.

 Net force  = weight  = mass x acceleration due to gravity

 Net force  = 2 x 9.8  = 19.6N downward

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