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yan [13]
4 years ago
15

A 1230 kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 7.07 m before contacting the beam,

and it drives the beam 15.9 cm into the ground before coming to rest. Find the magnitude of the average force the beam exerts on the pile driver while the pile driver is brought to rest. The acceleration of gravity is 9.8 m/s 2. Answer in units of N.
Physics
1 answer:
PilotLPTM [1.2K]4 years ago
4 0

Answer:

F_{avg} = 5.48 \times 10^5 N

Explanation:

As we know that initial and final speed of the beam is zero

so we can use energy conservation here to find the applied force

So we will have

work done by all the forces = change in kinetic energy of the beam

so we will have

W_g + W_{beam} = \Delta K

mg(L + x) - F_{avg} x = 0

1230(9.81)(7.07 + 0.159) = F_{avg} (0.159)

so we will have

87227.3 = F_{avg} (0.159)

F_{avg} = 5.48 \times 10^5 N

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A uniform solid sphere of radius r = 0.510 m and mass m = 15.5 kg turns counterclockwise about a vertical axis through its cente
klasskru [66]

Answer:

5.160384 kg*m²/s

Explanation:

The vector angular momentum P can be found using the following expression:

P = I * w

I refers to the inertia, that for a sphere is found using the expression:

I = \frac{2}{5} * m * r² = \frac{2}{5} * 15.5kg * (0.510m)² = 1.61262 kg*m².

The angular velocity w is given by the problem, and has a value of 3.2 rad/s.

Replacing the data we get:

P = 1.61262 kg*m² * 3.2 rad/s = 5.160384 kg*m²/s

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3 years ago
The pituitary gland releases chemicals knows as:
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3 years ago
How would seasons on earth be different if the earth was not tilted on its axis
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If the Earth's axis were 'straight' ... pefectly perpendicular to the ecliptic
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-- Day and night would be the same length ... every day of the year,
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5 0
4 years ago
John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. He is pulling horizontally wi
bulgar [2K]

Answer:

The mass of Laura and the sled combined is 887.5 kg

Explanation:

The total force due to weight of Laura and friction on the sled can be calculated as follows;

F_T = F_L+F_S

     = (400 + 310) N

     = 710 N

From Newton's second law of motion, "the rate of change of momentum is directly proportional to the applied force.

F_T = \frac{(M_L+M_S)V}{t}

where;

M_L is mass of Laura and

M_S is mass of sled

Mass of Laura and the sled combined is calculated as follows;

(M_L+M_S) = \frac{F_T*t}{V}

given

V = Δv = 4-0 = 4m/s

t = 5 s

(M_L+M_S) = \frac{710*5}{4}\\\\(M_L+M_S) =  887.5 kg

Therefore, the mass of Laura and the sled combined is 887.5 kg

4 0
3 years ago
What's the concept of mass ?
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