Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a = 
a= 
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
Answer:
Seriously I have no idea. I need help with my homework.
Explanation:
I really need help with my homework. Sorry
There's no general rule.
Displacement is the length of a straight line from start to finish, and distance is how far you actually traveled from start to finish.
The only thing we really know is that distance can never be shorter than displacement. So I guess the answer is:
<em>The numerical ratio of displacement to distance is always 1 or less</em>.
(But it has to be written ALL IN CAPITALS.)
It would do exactly what a rock or a frisbee does when you toss it.
After the engines cut off, it couldn't get any more energy from
anywhere, and after that, as it pushed air aside to get through,
and had air molecules scraping against it, those would slowly
rob kinetic energy from it. Sooner or later it would run out of
kinetic energy, start falling, and it would eventually make either
a big 'SPLOOSH' or else a big 'CRUNCH', depending on exactly
where it returned to Earth's surface.
Answer:
0m/s^2
Explanation:
have a beautiful day ahead