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yan [13]
3 years ago
15

A 1230 kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 7.07 m before contacting the beam,

and it drives the beam 15.9 cm into the ground before coming to rest. Find the magnitude of the average force the beam exerts on the pile driver while the pile driver is brought to rest. The acceleration of gravity is 9.8 m/s 2. Answer in units of N.
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

F_{avg} = 5.48 \times 10^5 N

Explanation:

As we know that initial and final speed of the beam is zero

so we can use energy conservation here to find the applied force

So we will have

work done by all the forces = change in kinetic energy of the beam

so we will have

W_g + W_{beam} = \Delta K

mg(L + x) - F_{avg} x = 0

1230(9.81)(7.07 + 0.159) = F_{avg} (0.159)

so we will have

87227.3 = F_{avg} (0.159)

F_{avg} = 5.48 \times 10^5 N

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6 0
2 years ago
On a frictionless surface how much force is necessary to accelerate a 0.49 kg object to the left at 4.8 m/s2?
Alenkasestr [34]

Answer:

<h2>2.35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

Hope this helps you

8 0
2 years ago
About how much of Earth's water is available for humans to use?
lesya692 [45]

Answer:

0.3 %

Explanation:

Earth cleans and replenishes the water supply through the hydrologic cycle. The earth has an abundance of water, but unfortunately, only a small percentage, is even usable by people.

5 0
3 years ago
A student connects a small solar panel to a 40 a resistor to make a simple circuit. The solar panel produces a voltage of 2 0.
Nastasia [14]
<h3>Solution for the above question : -</h3>

Ohm's law states that :

  • v = ir

the terms used are :

  • r = resistance
  • v = potential \:  \: difference
  • i  = current

let's solve for electric current :

  • 2 = i \times 40

  • i =  \dfrac{2}{40}

  • i = 0.05 \: A

  • i = 50 \: mA

\mathfrak{good\:  \: luck \:  \: for \:  \: your \:  \: assignment}

8 0
2 years ago
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Gre4nikov [31]

Answer:

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Explanation:

hope it helped tee hee

6 0
3 years ago
Read 2 more answers
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