To increase the acceleration due to gravity, we will place the new station in a shorter radius which is 1.2 RE.
<h3>What is acceleration due to gravity?</h3>
- This is free fall of an object under the influence of gravitational pull.
The acceleration due to gravity of the new station due to Earth's gravity is calculated as follows;
where;
- g is the acceleration due to gravity
- G is gravitational constant
- M is the mass of the earth
- R is the radius of the earth
To increase the acceleration due to gravity, the radius of the earth must be decreased. Thus, we will place the new station in a shorter radius which is 1.2 RE.
Learn more about acceleration due to gravity here: brainly.com/question/88039
Hi there!
On a level road:
∑F = Ff (Force due to friction)
The net force is the centripetal force, so:
mv²/r = Ff
Rewrite the force due to friction:
mv²/r = μmg
Cancel out the mass:
v²/r = μg
Solve for v:
v = √rμg
v = √(25)(9.81)(0.8) = 14.01 m/s
Answer: the lvl wud remain the same
Explanation: as per Archimedes Principle, the weight of the water displaced by the object is equal to the weight of the object. When the ship initially went into the pool, it wud hv displaced some water. When the anchor is dropped, the level does not change coz the anchor was already in the ship and no extra weight has been added, so the weight of the anchor has already been accounted for in the first place when the ship was first placed in the pool
