To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K$

Putting values in above equation, we get:

$\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm$

Thus the new pressure, if volume and amount of gas do not change is 2.40 atm

5 0

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Which is the best way to turn helium gas into liquid helium?

erma4kov [3.2K]

To create the liquid and superfluid states you cool down helium gas to a few degrees above absolute zero

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In what element will metallic bonding occur?

Hatshy [7]

D

A- Harvard university professor

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