Answer:
The total amount of heat released is 68.7 kJ
Explanation:
Given that:
mass of water = 94.0 g
moles of water = 94 / 18.02 = 5.216
80⁰C ------> 0⁰C --------> -30⁰C
Q1 = m Cp dT
= 94 x 4.184 x (0 - 80)
= -31463.68 J
= -31.43 kJ
Q2 = 6.01 x 10^3 x 5.216
= - 31348.16 J
= -31.35 kJ
Q3 = - 94 x 2.09 x 30
= - 5893.8 J
= -5.894 kJ
Total heat = Q1 + Q2 + Q3 = -31.43 kJ + (-31.35 kJ ) + (-5.894 kJ
) = -68.7 kJ
Total heat released = -68.7 kJ
Note that the "negative sign" simply indicates heat released, therefore no need to put it in the answer.
when you type your answer ... your body gets sick rid of waste through the skin
Answer:
The sum of the coefficients in the balanced equation is 11
Explanation:
A reaction where an organic compound reacts with oxygen to produce carbon dioxide and water is called combustion.
The balance reaction of combustion for methanol is:
2CH₃OH (l) + 3O₂(g) → 2CO₂(g) + 4H₂O (g)
Coefficients from stoichiometry are 2, 3, 2 and 4
Sum = 2 + 3 + 2 + 4 = 11
Answer:
Explanation:
Explanation:
As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.
In your case, you know that the empirical formula is
NH Cl
2
, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be
1:2:1.
What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.
Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.
molar mass empirical formula×n=molar mass compound
To get the molar mass of the empirical formula, use the molar masses of its constituent atoms
14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈
51.5 g/mol
This means that you have
51.5g/mol×n=51.5g/mol
As you can see, you have
n=1.
This means that the empirical formula and the molecular formula are equivalent,
NH Cl.
2
