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Tanya [424]
3 years ago
15

Asap PLEASE HELP!!!! Match these vocabulary words with their definitions.

Physics
1 answer:
lubasha [3.4K]3 years ago
3 0
1. Isotherm
2. Labrador current
3. Longitude
4. Gulf stream
5. Horse latitudes
6. Maritime
7. Middle latitude climates
8. North Atlantic drift

hope this helps

mark me brainliest please!
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An empty parallel plate capacitor is connected between the terminals of a 4.4-V battery and charged up. The capacitor is then di
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Answer:

d

Explanation:

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7 0
3 years ago
What is the resistance of a bulb of 4ow<br>connected in a line of 220v?<br>2​
inn [45]

Answer:

1210 ohm

Explanation:

Given :

P=40 W

V=220 V

Now,

P=\frac{V^{2} }{R} \\40=\frac{(220)^{2} }{R} \\40R=48400\\R=\frac{48400}{40} \\R=1210 ohm

Therefore, resistance of bulb will be 1210 ohm

8 0
3 years ago
if an object is moving with constant speed then its distance time graph will be a straight line. a) along time axis b) along dis
Varvara68 [4.7K]

Answer: I’m not sure but the time and distance will be increasing while they required the distance time so my answer is ((A))

Explanation:

5 0
3 years ago
A lightning flash releases about 1010J of electrical energy. Part A If all this energy is added to 50 kg of water (the amount of
zavuch27 [327]

Answer:

water is in the vapor state,

Explanation:

We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat

        E = Q₁ + Q_{L}

Where Q1 is the heat required to bring water from the current temperature to the boiling point

      Q₁ = m c_{e} ( T_{f} -T₀)

      Q₁ = 50 4180 (100 - 37)

      Q₁ = 1.317 10⁷ J

Let's calculate the energy so that all the water changes state

     Q_{L}  = m L

     Q_{L}  = 50 2,256 106

    Q_{L}  = 1,128 10⁸ J

Let's look for the energy needed to convert all the water into steam is

     Qt = Q₁ + Q_{L}  

     Qt = 1.317 107 + 11.28 107

     Qt = 12,597 10⁷ J

Let's calculate how much energy is left to heat the water vapor

     ΔE = E - Qt

     ΔE = 10¹⁰ - 12,597 10⁷

     ΔE = 1000 107 - 12,597 107

     ΔE = 987.4 10⁷ J

With this energy we heat the steam, clear the final temperature

     Q = ΔE = m c_{e} ( T_{f}-To)

    ( T_{f}-T₀) = ΔE / m c_{e}

      T_{f} = T₀ + ΔE / m c_{e}

      T_{f} = 100 + 987.4 10⁷ / (50 1970)

      T_{f} = 100 + 1,002 10⁵

      T_{f} = 1,003 10⁵ ° C

This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components

4 0
3 years ago
QUESTION 3 ( MARKS]
horrorfan [7]

Answer:

392 N

Explanation:

Draw a free body diagram of the rod.  There are four forces acting on the rod:

At the wall, you have horizontal and vertical reaction forces, Rx and Ry.

At the other end of the rod (point X), you have the weight of the sign pointing down, mg.

Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.

Sum of the moments at the wall:

∑τ = Iα

(T sin θ) L − (mg) L = 0

T sin θ − mg = 0

T = mg / sin θ

Given m = 20 kg and θ = 30.0°:

T = (20 kg) (9.8 m/s²) / (sin 30.0°)

T = 392 N

7 0
3 years ago
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