Answer:
1210 ohm
Explanation:
Given :
P=40 W
V=220 V
Now,

Therefore, resistance of bulb will be 1210 ohm
Answer: I’m not sure but the time and distance will be increasing while they required the distance time so my answer is ((A))
Explanation:
Answer:
water is in the vapor state,
Explanation:
We must use calorimetry equations to find the final water temperatures. We assume that all energy is transformed into heat
E = Q₁ + 
Where Q1 is the heat required to bring water from the current temperature to the boiling point
Q₁ = m
(
-T₀)
Q₁ = 50 4180 (100 - 37)
Q₁ = 1.317 10⁷ J
Let's calculate the energy so that all the water changes state
= m L
= 50 2,256 106
= 1,128 10⁸ J
Let's look for the energy needed to convert all the water into steam is
Qt = Q₁ +
Qt = 1.317 107 + 11.28 107
Qt = 12,597 10⁷ J
Let's calculate how much energy is left to heat the water vapor
ΔE = E - Qt
ΔE = 10¹⁰ - 12,597 10⁷
ΔE = 1000 107 - 12,597 107
ΔE = 987.4 10⁷ J
With this energy we heat the steam, clear the final temperature
Q = ΔE = m
(
-To)
(
-T₀) = ΔE / m 
= T₀ + ΔE / m 
= 100 + 987.4 10⁷ / (50 1970)
= 100 + 1,002 10⁵
= 1,003 10⁵ ° C
This result indicates that the water is in the vapor state, in realizing at this temperature the water will be dissociated into its hydrogen and oxygen components
Answer:
392 N
Explanation:
Draw a free body diagram of the rod. There are four forces acting on the rod:
At the wall, you have horizontal and vertical reaction forces, Rx and Ry.
At the other end of the rod (point X), you have the weight of the sign pointing down, mg.
Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.
Sum of the moments at the wall:
∑τ = Iα
(T sin θ) L − (mg) L = 0
T sin θ − mg = 0
T = mg / sin θ
Given m = 20 kg and θ = 30.0°:
T = (20 kg) (9.8 m/s²) / (sin 30.0°)
T = 392 N