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DiKsa [7]
4 years ago
15

Question is in the picture

Chemistry
1 answer:
wariber [46]4 years ago
8 0

Answer:

repelled

Explanation:

like charges repel one another

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What information is needed to determine the amount of moles in 1.6g of HCL?
alukav5142 [94]

Answer:

Molar mass and Mass

Explanation:

The relationship between mass and number of moles is given as;

Number of moles = Mass / Molar mass

Mass = 1.6 g

Molar mass of HCl = ( 1 + 35.5 ) = 36.5 g/mol

Number of moles = 1.6 g / 36.5 g/mol

Number of moles = 0.0438 mol

8 0
3 years ago
A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f
deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

           S = K_{b} \times ln \Omega

where,      S = entropy

             K_{b} = Boltzmann constant

             \Omega = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

     \Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega

                 = 1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)

                 = 1.38 \times 10^{-23} \times (-0.182)

                 = -0.251 \times 10^{-23}

or,             = -2.51 \times 10^{-24}

Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

8 0
3 years ago
g The following reaction is the first step in the production of nitric acid from ammonia. 4NH3(g) 5O2(g) → 4NO(g) 6H2O(g) Calcul
STatiana [176]

<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]

We are given:

\Delta H_f_{(NO(g))}=91.3kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-45.9kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ

Hence, the enthalpy of the reaction is coming out to be -902 kJ.

8 0
4 years ago
Consider the equilibrium reaction. 4A+B↽−−⇀3C After multiplying the reaction by a factor of 2, what is the new equilibrium equat
disa [49]
8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6
8 0
4 years ago
a sample of argon gas is cooled and its volume went from 380. mL to 250. mL. If its final temperature was -55.0C, what was its o
inn [45]

Answer:

The initial temperature was 58.4°C

Explanation:

Given the following data:

initial volume = V₁ = 380 mL = 0.38 L

final volume = V₂ = 250 mL = 0.25 L

final temperature = T₂ = -55°C = 218 K

According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:

V₁/T₁= V₂/T₂

So, we calculate the initial temperature (V₁) as follows:

T₁ = T₂/V₂ x V₁ = 218 K/(0.25 L) x 0.38 L = 331.36 K ≅ 331.4 K

Finally, we convert the initial temperature from K to °C:

T₁= 331.4 K - 273 = 58.4°C

6 0
3 years ago
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