6.11% w/v of Cu2+ implies that 6.11 g of Cu2+ is present in 100 ml of the solution
therefore, 250 ml of the solution would have: 250 ml * 6.11 g/100 ml = 15.275 g
# moles of Cu2+ = 15.275 g/63.546 g mole-1 = 0.2404 moles
1 mole of CuCl2 contain 1 mole of Cu2+ ion
Hence, 0.2404 moles of Cu2+ would correspond to 0.2404 moles of CuCl2
Molar mass of CuCl2 = 134.452 g/mole
The mass of CuCl2 required = 0.2404 moles * 134.452 g/mole = 32.32 grams
Answer:
The answer to your question is letter B
Explanation:
Incorrect name
A. acetic acid This name is correct for the acid with formula CH₃COOH
B. hydrocarbonate acid This is not the name for acid but for a molecule that has hydrogen and a metal.
C. hydrocyanic acid This name is correct for the inorganic molecule with formula HCN
D. sulfurous acid This name is correct and is the name of the inorganic molecule with formula H₂SO₃.
E. phosphoric acid This name is correct for the acid with formula H₃PO₄.
A2+. Group 2 elements form cations with 2+ charge.
