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3 years ago

5

Please solce thiss quesstion

1 answer:

noname [10]3 years ago

4 0

Answer:

Can you give a clearer question

Explanation:

pls give me points i have questions

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Two loudspeakers, A and B are driven by the same amplifier

DedPeter [7]

<h3><u>Complete Question </u></h3>

Q)Two loudspeakers, A and B, are driven by the same amplifier as shown and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. Consider point Q along the extension of the line connecting the speakers, 1.00 m to the right of speaker B. Both speakers emit sound waves that travel directly from the speaker to point Q. a) What is the lowest frequency for which constructive interference occurs at point Q? b) What is the lowest frequency for which destructive interference occurs at point Q? The speed of sound wave is 344 m/s.

Answer:

lowest frequency is 172 Hz. for n = 1

lowest frequency is 86 Hz for n = 0

Explanation:

(a) Constructive interference takes place when the path difference is n where n=1,2,3 ...

frequency f = v /λn

= v n / d

= n ( 344 / 2 )

= n ( 172 ) Hz.

lowest frequency is 172 Hz

b)Destructive interference takes place when the path difference is n/2 x where n=1,3,5 ...

λ = 4/2n+1

for n = 0

λ = 4m

f = 344/4

f = 86 Hz.

lowest frequency is 86 Hz

3 0

4 years ago

Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.6 cm and a current of 12 A. The bigger lo

puteri [66]

Answer:

the radius of bigger loop = 6 cm

Explanation:

given,

two concentric current loops

smaller loop radius = 3.6 cm

]current in smaller loop = 12 A

current in the bigger loop = 20 A

magnetic field at the center of loop = 0

Radius of the bigger loop = ?

$B_t = B_1 + B_2$

$0 = \dfrac{\mu_0I_1}{2R_1} +\dfrac{\mu_0I_2}{2R_2}$

now, on solving

$\dfrac{I_1}{R_1} = \dfrac{I_2}{R_2}$

$R_2 = I_2\dfrac{R_1}{I_1}$

= $20\times \dfrac{3.6}{12}$

= 6 cm

hence, the radius of bigger loop = 6 cm

7 0

3 years ago

When air pressure decreases, the mercury in a barometer _____.

siniylev [52]

Answer:

The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.

Explanation:

7 0

3 years ago

An electron and a proton, initially at rest, are pushed by the same force. Which of the two will have greater velocity?

yulyashka [42]

Answer:

B electron

Explanation:

electron will have greater velocity

7 0

3 years ago

A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi

Mamont248 [21]

Answer:

$a=368.97\ m/s^2$

Explanation:

Given that,

Initial angular velocity, $\omega=0$

Acceleration of the wheel, $\alpha =7\ rad/s^2$

Rotation, $\theta=14\ rotation=14\times 2\pi =87.96\ rad$

Let t is the time. Using second equation of kinematics can be calculated using time.

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s$

Let $\omega_f$ is the final angular velocity and a is the radial component of acceleration.

$\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s$

Radial component of acceleration,

$a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2$

So, the required acceleration on the edge of the wheel is $368.97\ m/s^2$ .

6 0

3 years ago