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tatiyna
3 years ago
15

What types of landforms are located in Florida? plaz i need help FAST

Physics
2 answers:
chubhunter [2.5K]3 years ago
8 0
The coastal plains generally consist of flat land, fronted by barrier islands, sandy beaches, coral reefs and sandbars. The low rolling-hills of the uplands area stretch across the Florida Panhandle. Here, the state's highest point, Britton Hill, rises to 345 ft.
nordsb [41]3 years ago
4 0

There are beaches.


You didnt add anny choices

Hope this helps Buddy!


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(a) How many fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit
Ainat [17]

Answer:

a

The number of fringe is  z  = 3 fringes

b

The  ratio is I = 0.2545I_o

Explanation:

a

 From the question we are told that

        The wavelength is  \lambda = 600 nm

        The distance between the slit is  d = 0.117mm = 0.117 *10^{-3} m

        The width of the slit is  a = 35.7 \mu m = 35.7 *10^{-6}m

let  z be the number of fringes that appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern is  and this mathematically represented as

             z = \frac{d}{a}

Substituting values

             z = \frac{0.117*10^{-3}}{35.7 *10^{-6}}  

             z  = 3 fringes

b

   From the question  we are told that the order  of the bright fringe is  n = 3

   Generally the intensity of  a pattern  is mathematically represented as

                 I = I_o cos^2 [\frac{\pi d sin \theta}{\lambda} ][\frac{sin (\pi a sin \frac{\theta}{\lambda } )}{\pi a sin \frac{\theta}{\lambda} } ]

Where I_o is the intensity  of the  central fringe

 And  Generally  sin \theta = \frac{n \lambda }{d}

               I = I_o co^2 [ \frac{\pi (\frac{n \lambda}{d} )}{\lambda} ] [\frac{\frac{sin (\pi a (\frac{n \lambda}{d} ))}{\lambda} }{\frac{\pi a (\frac{n \lambda}{d} )}{\lambda} } ]

               I = I_o cos^2 (n \pi)[\frac{\frac{sin(\pi a (\frac{n \lambda}{d} ))}{\lambda} )}{ \frac{ \pi a (\frac{n \lambda }{d} )}{\lambda} } ]

               I = I_o cos^2 (3 \pi) [\frac{sin (\frac{3 \pi }{6} )}{\frac{3 \pi}{6} } ]

                I = I_o (1)(0.2545)

                  I = 0.2545I_o

6 0
3 years ago
Manipulate p+x=r to solve for x
Tanzania [10]
X=r-p. Maybe I don't understand, but I am assuming that you need to isolate for X? you simply subtract p from both sides.<span />
4 0
2 years ago
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How many like does it take to get to the center of a tosipop
dmitriy555 [2]
252-364 licks 

I'm not sure if it's correct or not 
4 0
3 years ago
Read 2 more answers
2.
anzhelika [568]

Answer:

44.72m/s

Explanation:

use th formula:vf²=vi²at

and then substitute the values

remember the units

8 0
2 years ago
A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point
PtichkaEL [24]

Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

F is magnetic force.

B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

8 0
3 years ago
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