Answer: 0.145 seconds
Explanation:
Given that Roger Clemens could routinely throw a fastball at a horizontal speed of 119.7 m/s. How long did the ball take to reach home plate 17.3 m away
Since the speed is horizontal
Using the formula for speed which is
Speed = distance/time
Where
Speed = 119.7 m/s
Distance covered = 17.3 m
Time is what we are looking for
Substitute all the parameters into the formula
119.7 = 17.3/ time
Make time the subject of formula
Time = 17.3 / 119.7
Time = 0.145 seconds.
Therefore, it will take 0.145 seconds to reach the home plates
Answer:
T = 540 N (to two significant digits)
Explanation:
Let the crate dimension L be from strap attachment to floor contact
Let T be the strap tension
sum moments about the floor contact point to zero
mg[½Lcos25] - Tsin61[Lcos25] + Tcos61[Lsin25] = 0
L is common to all terms, so divides out.
½(71)(9.8)cos25 = T(sin61cos25 - cos61sin25)
T = (71)(9.8)cos25 / (2(sin61cos25 - cos61sin25))
T = 536.428020...
Your average speed was
(100 m) / (13.8 s) = 7.25 m/s .
If you finished 0.001s ahead of him, then at your average speed, that corresponds to
(7.25 m/s) x (0.001 s) = 0.00725 m
That's 7.25 millimeters ... about 0.28 of an inch !
NOTE:. I think this is only valid if your speed was a constant ~7.25 m/s all the way.
