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kondaur [170]
3 years ago
15

Assume the recommended single dose of an antihistamine for a child weighing 36–47 lbs is 1.50 teaspoons (tsp) . If 1.00 tsp cont

ains 12.5 mg per 5 mL of the active ingredient in the antihistamine, how many milligrams of active ingredient does the recommended dose for a child weighing 36–47 lbs contain? Assume that 1.00 tsp = 5 mL .
Chemistry
1 answer:
Scilla [17]3 years ago
3 0

Answer:

18.75 milligrams of active ingredient is the recommended dose for a child weighing 36–47 lbs .

Explanation:

Recommended dose of an antihistamine for a child weighing 36–47 lbs = 1.50 tsp

1 table spoon of antihistamine has 12.5 mg per 5 mL of dose.

Amount of dose in 1 teaspoon = \frac{12.5 mg}{5 mL}=2.5 mg/mL

Volume of 1 tsp = 5 ml

Volume of 1.50 teaspoon = 5 mL\times 1.50 =7.50 mL

Amount of antihistamine in 7.50 mL :

=2.5 mg/mL\times 7.50 mL=18.75 mg

18.75 milligrams of active ingredient is the recommended dose for a child weighing 36–47 lbs .

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To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

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135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

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It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

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Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

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<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

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