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Thepotemich [5.8K]
2 years ago
14

Calculate the percent by mass of a solution made from 14 g nacl (the solute) and 61 g water

Chemistry
1 answer:
shtirl [24]2 years ago
5 0

The percent by mass of  an answer  made from 14 g NaCl (the solute) and 61 g water is 18.66%

14 g + 61 g =75.0 g - mass of the solution

mass % = (mass solute/ mass solution)*100% = (14/75.0)*100% =

= 0.186*100% =18.66%.

What is the percent by mass?

Mass percent is another method of expressing the composition of the solution mixture. It describes the amount of solute (grams) present in 100 gm of the solution.

To know more about percent by mass go to the given link :

brainly.com/question/20393858

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Given that a 19.00 g milk chocolate bar contains 11.50 g of sugar, calculate the percentage of sugar present in 19.00
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2 years ago
At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.
natka813 [3]

Explanation:

The given data is as follows.

             T = 298 K,          \Delta H^{o} = -5645 kJ/mol

          \Delta G^{o} = -5798 kJ/mol

Relation between \Delta H and \Delta G are as follows.

          \Delta G^{o} = \Delta H^{o} - T \Delta S^{o}    

             -5798 kJ/mol = -5645 kJ/mol - 298 \times \Delta S^{o}

                       -153 kJ/mol = -298 \times \Delta S^{o}

                    \Delta S^{o} = 0.513 kJ/mol K

Now, temperature is 37^{o}C = (37 + 273) K = 310 K

Since,        \Delta G = \Delta H^{o} - T \Delta S^{o}

                            = -5645 kJ/mol - 310 K \times 0.513 kJ/mol K

                            = (-5645 kJ/mol - 159.03 kJ/mol)

                            = -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

            \Delta G = \Delta G_{310 K} - \Delta G_{298 K}

                           = -5804.03 kJ/mol - (-5798 kJ/mol)

                           = -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0
3 years ago
What is the hydrogen concentration of a solution with a pH of 2.1?
Black_prince [1.1K]

Answer:

8×10^(-3) mol/L

Explanation:

The formula for finding the hydrogen ion concentration is...

[H⁺] = 10^-ph

[H⁺] = 10^(-2.1)

[H⁺] = 0.00794...mol/L = 8×10^(-3) mol/L

The answer is to 1 significant digit because the pH has one decimal place.

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