The solution to the binomial expression by using Pascal's triangle is:



<h3>How can we use Pascal's triangle to expand a binomial expression?</h3>
Pascal's triangle can be used to calculate the coefficients of the expansion of (a+b)ⁿ by taking the exponent (n) and adding the value of 1 to it. The coefficients will correspond with the line (n+1) of the triangle.
We can have the Pascal tree triangle expressed as follows:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
--- --- --- --- --- --- --- --- --- --- --- --- --- --- ---
From the given information:
The expansion of (3x-4y)^11 will correspond to line 11.
Using the general formula for the Pascal triangle:

The solution to the expansion of the binomial (3x-4y)^11 can be computed as:



Learn more about Pascal's triangle here:
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Answer:
Your answer should be A. You fell sharply behind your expected schedule with regard to saving
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
They are parallel lines basically, ingnore the measurements and the traingle, they were put there to confuse you.
Hope this helps
Never30
Answer:
$26 dollars
Step-by-step explanation: when you divide 156 divided by 6 you get 26
Answers:
So the solution is (x,y) = (4, -1)
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Work Shown:
6x + 7y = 17
6x + 7( y ) = 17
6x + 7( -3x+11 ) = 17 ... replace every copy of y with -3x+11
6x - 21x + 77 = 17
-15x = 17-77
-15x = -60
x = -60/(-15)
x = 4
We'll use this x value to find y
y = -3x+11
y = -3(4)+11 ... replace x with 4
y = -12+11
y = -1
We have x = 4 and y = -1 pair up together to give us the solution (x,y) = (4, -1)
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To check the solution, we plug x = 4 and y = -1 into each equation
Plugging the values into the first equation leads to...
y = -3x+11
-1 = -3(4)+11
-1 = -1
This is effectively already done in the last part of the previous section. But it doesn't hurt to verify like this regardless.
We'll need to verify the second equation as well.
6x + 7y = 17
6(4) + 7(-1) = 17
24 - 7 = 17
17 = 17
We get a true equation, so the solution is confirmed with both equations. Overall, the solution to the system of equations is confirmed. This system is independent and consistent.