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koban [17]
4 years ago
15

If 5.0 moles of C3H8 react, how many molecules of water are formed?

Chemistry
1 answer:
artcher [175]4 years ago
8 0
Balance Chemical Equation for combustion of Propane is as follow,

                         C₃H₈  +  5 O₂    →    3 CO₂  +  4 H₂O

According to equation,

              1 mole of C₃H₈ on combustion gives  =  4 moles of H₂O
So,
        5 moles of C₃H₈ on combustion will give  =  X moles of H₂O

Solving for X,
                                    X  =  (5 mol × 4 mol) ÷ 1 mole

                                    X  =  20 moles of H₂O

Calculating number of molecules for 20 moles of H₂O,
As,
                        1 mole of H₂O contains  =  6.022 × 10²³ molecules
So,
                20 moles of H₂O will contain  =  X molecules

Solving for X,
                                 X  =  (20 mole × 6.022 × 10²³ molecules) ÷ 1 mol

                                 X  =  1.20 ×10²⁵ Molecules of H₂O
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What is the percent composition of MgO2H2
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41.38 % Mg

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Explanation:

What is the percent composition of magnesium hydroxide Mg(OH)₂?

To find the percent composition we follow the next algorithm.

First we calculate the molar mass of Mg(OH)₂:

molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2

molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole

Now we devise the next reasoning:

if in         58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H

then in   100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H

X = (100 × 24) / 58 = 41.38 % Mg

X = (100 × 32) / 58 = 55.17 % O

X = (100 × 2) / 58 = 3.45 % H

Learn more about:

percent composition

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