<h2>
Answer:
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The velocity of a satellite describing a circular orbit is <u>constant</u> and defined by the following expression:
(1)
Where:
is the gravity constant
the mass of the massive body around which the satellite is orbiting
the radius of the orbit (measured from the center of the planet to the satellite).
Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. I<u>t depends on the mass of the massive body.</u>
In addition, this orbital speed is constant because at all times <u>both the kinetic energy and the potential remain constant</u> in a circular (closed) orbit.
Answer:
a₁ = 0.63 m/s² (East)
a₂ = -1.18 m/s² (West)
Explanation:
m₁ = 95 Kg
m₂ = 51 Kg
F = 60 N
a₁ = ?
a₂ = ?
To get the acceleration (magnitude and direction) of the man we apply
∑Fx = m*a (⇒)
F = m₁*a₁ ⇒ 60 N = 95 Kg*a₁
⇒ a₁ = (60N / 95Kg) = 0.63 m/s² (⇒) East
To get the acceleration (magnitude and direction) of the woman we apply
∑Fx = m*a (⇒)
F = -m₂*a₂ ⇒ 60 N = -51 Kg*a₂
⇒ a₂ = (60N / 51Kg) = -1.18 m/s² (West)
For every case we apply Newton’s 3
d Law
Answer:
Part a)
Mass of m2 is given as
Part b)
Angular acceleration is given as
Part c)
Tension in the rope is given as
Explanation:
Part a)
When m1 and m2 both connected to the cylinder then the system is at rest
so we can use torque balance here
Part b)
When block m_2 is removed then system becomes unstable
so force equation of mass m1
also we have
now we have
so angular acceleration is given as
Part c)
Tension in the rope is given as
