Question

Find the net work done by friction on the body of a snake slithering in a complete circle of 1.04 m radius. The coefficient of friction between the ground and the snake is 0.25, and the snake's weight is 78.0 N.

Answer 1

Answer:

The net work done by friction is 127.42 J.

Explanation:

Given that,

Radius = 1.04 m

Coefficient of friction = 0.25

Weight = 78.0 N

We need to calculate the work done

The work done is the product of force and displacement.

$work\ done = kF\cdot d$

$work\ done =k\times W\times 2\pi r$

Here, F = mg = W(weight)

$work\ done = 0.25\times78.0\times2\pi\times1.04$

$work\ done = 127.42\ J$

Hence, The net work done by friction is 127.42 J.