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-BARSIC- [3]
2 years ago
5

Find the net work done by friction on the body of a snake slithering in a complete circle of 1.04 m radius. The coefficient of f

riction between the ground and the snake is 0.25, and the snake's weight is 78.0 N.
Physics
1 answer:
Firdavs [7]2 years ago
7 0

Answer:

The net work done by friction is 127.42 J.

Explanation:

Given that,

Radius = 1.04 m

Coefficient of friction = 0.25

Weight = 78.0 N

We need to calculate the work done

The work done is the product of force and displacement.

work\ done = kF\cdot d

work\ done =k\times W\times 2\pi r

Here, F = mg = W(weight)

work\ done = 0.25\times78.0\times2\pi\times1.04

work\ done = 127.42\ J

Hence, The net work done by friction is 127.42 J.

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It will take about 1 hour and 12 minutes.

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7 0
2 years ago
A wire 6.90 m long with diameter of 2.15 mm has a resistance of 0.0320 Ω. Find the resistivity of the material of the wire. rho
spayn [35]
<h2>Answer:</h2>

1.68 x 10⁻⁸Ωm

<h2>Explanation:</h2>

The resistance (R) of a wire is related to its length(L), its material resistivity(ρ) and its crossectional area(A) as follows;

R = ρL/A               ------------------------(i)

Where;

A = πd² / 4              [where d = diameter of the wire]

From the question;

L = 6.90m

d = 2.15mm = 0.00215m

R = 0.0320Ω

First calculate the crossectional area (A) of the wire as follows;

A = πd² / 4      

[Take π = 3.142]

d = 0.00215m

∴ A = 3.142 x (0.00215)² / 4

∴ A = 0.000003631m²

Now, substitute the values of A, L, and R into equation (i) as follows;

R = ρL/A

0.0320 = ρ x 6.90 / 0.000003631

0.0320 = 1900302.95 x ρ

Solve for ρ;

=> ρ = 0.0320 / 1900302.95

=> ρ = 1.68 x 10⁻⁸Ωm

Therefore, the resistivity of the material of the wire is 1.68 x 10⁻⁸Ωm

4 0
2 years ago
Development occurs:
Alex73 [517]

Answer:

D

Explanation:

:(

4 0
2 years ago
PLEASE HELP ASAP!! <br><br> What do you think engineers could do to prevent sinkholes in Florida?
padilas [110]
I think they can use more durable materials.
8 0
2 years ago
Julie is cycling at a speed of 3.4 meters/second. If the combined mass of the bicycle and Julie is 30 kilograms, what is the kin
nexus9112 [7]

Answer:

A

Explanation:

KE = 1/2 mv^2

=1/2(30kg)( 3.4 m/s)^2

=173.4 joules

=1.7×10^2 joules

6 0
3 years ago
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