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Crank
3 years ago
9

Using a slotted line, the following results were obtained:

Physics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

Z_L=67 - j16.4Ω

Explanation:

Given that

d(min,0)= 4 cm

d(min,1)= 14 cm

Voltage standingwave ratio = 1.5

Zo = 50 Ω

We know that

d(min,1) - d(min,0) = λ/2

Now by putting the values

14 - 4 = λ/2

λ = 20 cm

We also know that

β=2π/λ

β=2π/0.2 = 10π rad/m

So we can say that

θr= 2β d(min,n) - (2 n + 1)π rad

θr=2×10π ×0.04 −π = -0.2 π rad

We know that

π rad = 180 °

θr= = -0.2 π rad= -36 °

We know that

\Gamma =\dfrac{S-1}{S+1}

Here S= 1.5

\Gamma =\dfrac{S-1}{S+1}

\Gamma =\dfrac{1.5-1}{1.5+1}

\Gamma =0.2

Z_L=Z_o\dfrac{1+\Gamma }{1-\Gamma }

by putting the values

Z_L=50\times \dfrac{1+0.2e^{-j36^{\circ}} }{1-0.2e^{-j36^{\circ}} }

Z_L=67 - j16.4Ω

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<em>1.</em> <em>39068.07 N</em>

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depth of water h = 10 m

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pressure due to depth of water = pgh

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<em>The right side is a hemisphere with the same diameter, therefore surface area is half of the left plug</em>

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force F required to lift right plug =  199326.9  x 0.098 =<em> 19534.036 N</em>

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