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Crank
4 years ago
9

Using a slotted line, the following results were obtained:

Physics
1 answer:
MAVERICK [17]4 years ago
6 0

Answer:

Z_L=67 - j16.4Ω

Explanation:

Given that

d(min,0)= 4 cm

d(min,1)= 14 cm

Voltage standingwave ratio = 1.5

Zo = 50 Ω

We know that

d(min,1) - d(min,0) = λ/2

Now by putting the values

14 - 4 = λ/2

λ = 20 cm

We also know that

β=2π/λ

β=2π/0.2 = 10π rad/m

So we can say that

θr= 2β d(min,n) - (2 n + 1)π rad

θr=2×10π ×0.04 −π = -0.2 π rad

We know that

π rad = 180 °

θr= = -0.2 π rad= -36 °

We know that

\Gamma =\dfrac{S-1}{S+1}

Here S= 1.5

\Gamma =\dfrac{S-1}{S+1}

\Gamma =\dfrac{1.5-1}{1.5+1}

\Gamma =0.2

Z_L=Z_o\dfrac{1+\Gamma }{1-\Gamma }

by putting the values

Z_L=50\times \dfrac{1+0.2e^{-j36^{\circ}} }{1-0.2e^{-j36^{\circ}} }

Z_L=67 - j16.4Ω

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Ksju [112]

1) 1.028 m/s^2

We can solve this part by using Newton's second law:

F=ma (1)

where

F is the net force

m is the mass

a is the acceleration

There are two forces acting on the boat:

F_1= 2.90 \cdot 10^3 N forward

F_2 = 1.69\cdot 10^3 N backward

So the net force is

F=2.90\cdot 10^3-1.69\cdot 10^3=1.21\cdot 10^3 N

We know that the mass of the boat is

m = 1177.5 kg

So we can now use eq.(1) to find the acceleration:

a=\frac{F}{m}=\frac{1.21\cdot 10^3}{1177.5}=1.028 m/s^2

2) 161.0 m

We can solve this part by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance travelled

u is the initial velocity

t is the time

a is the acceleration

Here we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

Substituting t = 17.7 s, we find the distance covered:

s=0+\frac{1}{2}(1.028)(17.7)^2=161.0 m

3) 18.2 m/s

The speed of the boat can be found with the following suvat equation

v=u+at

where

v is the final velocity

u is the initial velocity

t is the time

a is the acceleration

In this case we have

u = 0 (the boat starts from rest)

a=1.028 m/s^2

And substituting t = 17.7 s, we find the final velocity:

v=0+(1.028)(17.7)=18.2 m/s

And the speed is just the magnitude of the velocity, so 18.2 m/s.

6 0
4 years ago
How many energy levels do the electrons in oxygen occupy?
elixir [45]
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4 years ago
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We know that charged objects with the same sign repel each other and objects charged with opposite signs attract. What happens w
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solution:

When an uncharged conducting object brought near to a charged insulating object there is a force on the conducting object to move the electrons within it to opposite sides of the conductor. That means there is a separation of charges in the conducting object in the presence of the charged insulating object near to it but the charge on the conducting object is neutral.

Thus, the conducting object is uncharged.

There is a force of attraction between the uncharged conducting object and the insulating object when it brought near to the insulating object.

Thus, there is a force on the conducting object.

The conductor remains uncharged and a force is exerted on it.


3 0
3 years ago
If you change the mass of a moving object, you change its _______.
Paul [167]
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3 years ago
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Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa
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.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

y=0.455m

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L=1.62 m

Now the angle can be find as,

tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62})  \\\theta=15.68^{\circ}

Now the grating distance is,

d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m

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So,

\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm

Therefore the wavelength of laser light is 491.4 nm.

3 0
3 years ago
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