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dimaraw [331]
3 years ago
8

Which is true about the resistivities of a metal and a semiconductor as the temperature is increased?

Physics
2 answers:
allochka39001 [22]3 years ago
7 0

Answer:

The resistivity of metals decreases on increase in temperature whereas the resistivity of semiconductors increases with increase in temperature.

Explanation:

The majority charge carriers in metals are electrons which are explained by the electron-sea model. The electron sea model considers metal to have a sea of conducting electrons in between the nucleus arrangement.

The nucleus is bind firmly within the lattice structure and when the temperature has increased this accounts for the lattice vibrations as a result offering obstructions to the valence electrons which increases its bulk resistivity.

The variation in the resistivity of metal is given by:

\rho=\rho_0[1+\alpha_t(T-T_0)]

where:

\alpha_t=temperature coefficient of resistivity which is defined as the fractional change in resistivity per unit change in temperature.

\rm \rho\ and\ \rho_0\ are\ the\ resistivity\ at\ temperature\ T\ and\ T_0\ respectively

At temperatures 500 K above the room temperature we have the variation of resistivity of the metal in a linear manner.

  • For semiconductors, the value of coefficient of resistivity is negative which implies that the resistivity of semiconductors decreases as temperature increases.
MAVERICK [17]3 years ago
4 0

Answer:

Explanation:

According to the electrical conductivity, there are three types of materials:

Metals are the conductors which allows the electric current to flow through them. For example, iron , copper, silver, etc.

As the temperature of a metal increases the resistivity also increases.

Semiconductors are the material which are insulators at room temperature but they behaves like a conductor as the temperature increases.

The resistivity of a semiconductor decreases as the temperature increases.

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yawa3891 [41]

Answer:

2 m = E / c^2      where m is mass of electron

E = h v     where v is the frequency ( nu) of the incident photon

E = h c / y      where y is the incident wavelength (lambda)

2 m = h / (c y)

y = h / (2 m c)      wavelength required

y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8)  m

y = 3.31 / 27.3 E-11 m

y = 1.21 E -12 m   = .0121 Angstrom units

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3 years ago
What is being transferred as you do work?<br> A. Energy<br> B. Power<br> C. Heat<br> D. Strength
r-ruslan [8.4K]

\huge\bold{\purple{\bold{⚡A. Energy⚡}}}

\huge\underline\mathtt\colorbox{cyan}{Reason:}

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4 0
3 years ago
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a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

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3 years ago
If a proton and an electron are released when they are 7.00×10−10 m apart (typical atomic distances), find the initial accelerat
Ugo [173]

Answer:

The acceleration of the proton is 2.823 x 10¹⁷ m/s²

The acceleration of the electron is 5.175 x 10²⁰ m/s²

Explanation:

Given;

distance between the electron and proton, r = 7 x 10⁻¹⁰ m

mass of proton, m_p = 1.67 x 10⁻²⁷ kg

mass of electron, m_e = 9.11 x 10⁻³¹ kg

The attractive force between the two charges is given by Coulomb's law;

F = \frac{k(q_p)(q_e)}{r^2}

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/c²

F = \frac{k(q_p)(q_e)}{r^2} \\\\F = \frac{(9*10^9)(1.602*10^{-19})(1.602*10^{-19})}{(7*10^{-10})^2} \\\\F = 4.714 *10^{-10} \ N

Acceleration of proton is given by;

F = ma

F = m_pa_p\\\\a_p = \frac{F}{m_p}\\\\a_p = \frac{4.714*10^{-10}}{1.67*10^{-27}}\\\\a_p = 2.823 *10^{17} \ m/s^2

Acceleration of the electron is given by;

F = m_ea_e\\\\a_e = \frac{F}{m_e}\\\\a_e = \frac{4.714*10^{-10}}{9.11*10^{-31}}\\\\a_e = 5.175 *10^{20} \ m/s^2

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Makovka662 [10]

Answer:

True.

Explanation:

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Hence, the statement is true.

3 0
3 years ago
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