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Ludmilka [50]
3 years ago
14

7. Consumers can be predators, prey, scavengers, herbivores omnivoree, or carnivore: What is the common characteristic of all co

nsumer: A Create their own food B. Must eat to get energy C. Hunt for live animals D. Will eat anything​
Physics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

B. Must eat to get energy

Explanation:

The common characteristics of all consumers is that they must eat to get energy. This way, they are termed heterotrophs.

Heterotrophs are organisms that cannot make their own food. They must eat other organisms to obtain nutrition for energy needs.

Plants do not do this. They are autotrophs in that they simply make their own food.

They use this food to obtain energy for their living activities.

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As the particles in a soup reach the bolling point what happens
ICE Princess25 [194]

Answer:

Once the particles of a liquid reach its boiling point, additional heat would cause the liquid particles to boil off or vaporize.

Explanation:

4 0
3 years ago
Which element below has chemical properties similar to the chemical properties of fluorine.
SVETLANKA909090 [29]
For number one the answer is Iodine because it is in the same group as fluorine. For number two the answer is Germanium for the same reason. For number three the answer is Aluminum for the same reason.
4 0
3 years ago
Two identical cars are parked in the sun on a warm day. One car is black and the other is white. Both cars are parked for three
cestrela7 [59]

Answer:

black will be hotter because black paint absorbs light and white reflects it.

4 0
3 years ago
Read 2 more answers
A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

3 0
3 years ago
A gray kangaroo can bound across level ground with each jump carrying it 9.1 m from the takeoff point. Typically the kangaroo le
Alona [7]

Answer:

u = 10.63 m/s

h = 1.10 m

Explanation:

For Take-off speed ..

by using the standard range equation we have

R = u² sin2θ/g

R = 9.1 m

θ = 26º,

Initial velocity = u

solving for u

u² = \frac{Rg}{sin2\theta}

u^2 = \frac{9.1 x 9.80}{sin26}

u^2 = 113.17

u = 10.63 m/s

for Max height

using the standard h(max) equation ..

v^2 = (v_osin\theta)^2 -2gh

h =\frac{(v_o^2sin\theta)^2}{2g}

h  =  \frac{(113.17)(sin26)^2}{(2 x 9.80)}}

h = 1.10 m

7 0
3 years ago
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