Answer:
The position of the first dark spot on the positive side of the central maximum is 1.26 mm.
Explanation:
Given that,
Wavelength of light is 633 nm.
Slit width, d = 0.5 mm
The diffraction pattern forms on a screen 1 m away from the slit. We need to find the position of the first dark spot on the positive side of the central maximum.
For destructive interference :
Y is the distance of the minima from central maximum
Here, n = 1
So, the position of the first dark spot on the positive side of the central maximum is 1.26 mm.
Answer:
187.37 m
Explanation:
The wavelength of an electromagnetic wave is given by:
where
c is the speed of light
f is the frequency
We see that the wavelength is inversely proportional to the frequency: this means that the shortest am wavelength will occur at the highest am frequency, which is
And substituting also the speed of light
We find the wavelength:
Answer:
432 units
Explanation:
Let the charges be q and Q separated by a distance r. The electrostatic force , F = kqQ/r² = 72 units. If q = 2q and Q = 3Q, then the new electrostatic force is
F = k × 2q × 3Q/r² = 6kqQ/r² = 6 × 72 = 432 units
The <span>actinides and lanthanides.</span>
Answer:
Explanation:
Due to changing magnetic field , there will be emf induced in the region . EMF induced will create electric field which will be circular in shape and will be uniform along its circular path
The magnitude of circular electric field can be calculated as follows
We should apply Faraday law of electro magnetic induction
e = - dФ / dt = - ∫ E dl
Here Ф = π r² B
π r² dB / dt = - ∫ E dl
π r² dB / dt = E x 2π r
E = - r / 2 x dB / dt
For a circular electric field having a particular radius , magnitude of field will be constant .
The direction of electric field will be known by lenz's law
In the given case , magnetic field is upwards and it is reducing , therefore electric field induced will be such as to prevent this change of flux.
So electric field will be anticlock-wise . Hence direction of acceleration will also be anticlock-wise on proton at 1.5 cm from the centre.
