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Ludmilka [50]
3 years ago
14

7. Consumers can be predators, prey, scavengers, herbivores omnivoree, or carnivore: What is the common characteristic of all co

nsumer: A Create their own food B. Must eat to get energy C. Hunt for live animals D. Will eat anything​
Physics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

B. Must eat to get energy

Explanation:

The common characteristics of all consumers is that they must eat to get energy. This way, they are termed heterotrophs.

Heterotrophs are organisms that cannot make their own food. They must eat other organisms to obtain nutrition for energy needs.

Plants do not do this. They are autotrophs in that they simply make their own food.

They use this food to obtain energy for their living activities.

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A car travels straight for 20 miles on a road that is 30° north of east. What is the east component of the car’s displacement
Over [174]

The east component of the cars displacement is 17.3 miles.

Trigonometric ratio is used to show the relationship between the sides of a right angled triangle and its angles.

Let x represent the east component of the cars displacement.

Using trigonometric ratio:

cos(30) = x / 20

x = 20 * cos(30)

x = 17.3 miles

The east component of the cars displacement is 17.3 miles.

Find out more on Trigonometric ratio at: brainly.com/question/1201366

4 0
2 years ago
A. How does doubling the height of the cylinder affect its GPE?
vampirchik [111]

The answer would be:

Doubling the height will increase the amount of Joules produced.


8 0
3 years ago
Which of the following is an example of rolling friction?
il63 [147K]

Answer:

O bike tires on the road as you ride

Explanation:

is the rolling friction

7 0
3 years ago
Read 2 more answers
Please help with both will give brainlist worth 20
REY [17]

Answer:

Second bubble

Explanation:

Its going up

7 0
3 years ago
To receive AM radio, you want an RLC circuit that can be made to resonate at any frequency between 500 and 1650 kHz. This is acc
levacccp [35]

The formula for resonant frequency is:

f_0=\frac{1}{2\pi\sqrt{LC} }

Given information:

f_{0\text{,small}}=500 \text{ kHz}\\f_{0\text{,large}}=1650 \text{ kHz}\\L=3.83\text{ } \mu \text{H}

Plug in the given values to find one value of capacitance:

500 \text{ kHz}=\frac{1}{2\pi\sqrt{C(3.83\text{ } \mu \text{H})} }\\C=2.645*10^{-8} \text{ F}=26.45 \text{ nF}

Plug in the given values to find the other value of capacitance:

1650 \text{ kHz}=\frac{1}{2\pi\sqrt{C(3.83\text{ } \mu \text{H})} }\\C=2.429*10^{-8} \text{ F}=2.429 \text{ nF}

This gives a range of 2.429 nF to 26.45 nF.

With significant figures taken into account, the range of capacitance is 2.43 nF to 30 nF.

6 0
3 years ago
Read 2 more answers
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