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Luba_88 [7]
3 years ago
9

a fence post is 13 feet tall. a chain is attached to the fence post and fastened to the ground 7 feet from the base of the fence

post. what is the length of the chain?

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
You draw a diagram of the fence post and then you use the measurements to find the length of the chain using the pythagorean theorem. The answer is \sqrt{218} or 14.8

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Write a numerical expression for this word phrase.
olya-2409 [2.1K]

Step-by-step explanation:

difference of 9 and 2 is 9-2

product of 4 and (9-2)

4*(9-2)

4 0
3 years ago
Please help me get an answer
balandron [24]
The y intercept in the scatter plot means that at 0 years working, you will get paid $8 per hr. The y intercept can be represented by the ordered pair (0,8). The independent variable is the # of years and the dependent variable is pay per hour.

Hope this helped :)
3 0
3 years ago
Let f(x) = 2x–8 and g(x) = x + 2. Find f(g(x)) and g(f(x)).
Anna71 [15]

Answer:

g(f(x)) = 2x - 6

f(g(x)) = 2x - 4

Step-by-step explanation:

g(f(x)) = 2x - 8 + 2

g(f(x)) = 2x - 6

f(g(x)) = 2(x + 2) - 8

f(g(x)) = 2x - 4

8 0
3 years ago
Read 2 more answers
A group of 45 students went to a basketball game.
monitta

Answer:

See below. (C*a) + (P*b) = M

Step-by-step explanation:

amount of students = 45

amount of candy per student = 1

amount of popcorn per student = 1

Let "S" be the total amount of students

Let "C" be the total amount of candy

Let "P" be the total amount of popcorn

Let "T" be the total number of snacks

Let "a" be the price per candy

Let "b" be the price per popcorn

Let "M" be the total amount of money spent at the game

The price of the candy is unknown.

The price of the popcorn is unknown.

The total amount of money spent at the game is unknown.

(C*a) + (P*b) = M

I am not sure what you are asking for but, here is what I drew up for you. Hope this helps!

7 0
3 years ago
It says to place points on them but i still don't get it. help please.
xxTIMURxx [149]

Answer: A'=(1, 3); B'=(-3, 4);C'=(3, 0); D'=(-2, 5)

You can check the PNG attached as well.

Step-by-step explanation:

You need to represent the symmetry of every given points respet to the line

y = 2

In that case, the line beeing paralell to the x- axis, x- value of the symmetry is the same of the given point and y = 2 is the middle between both points.

Point A(1, 1)

x_{A} = 1\\ x_{A'} = 1 \\\\\frac{y_{A} +y_{A'} }{2} =2\\y_{A'} = 4 - y_{A} = 4 - 1 = 3

Point B(-3, 0)

x_{B} = 1\\ x_{B'} = 1 \\\\\frac{y_{B} +y_{B'} }{2} =2\\y_{B'} = 4 - y_{B} = 4 - 0 = 4

Point C(3, 4)

x_{C} = 1\\ x_{C'} = 1 \\\\\frac{y_{C} +y_{C'} }{2} =2\\y_{C'} = 4 - y_{C} = 4 - 4 = 0

Point D(-2, -1)

x_{D} = 1\\ x_{D'} = 1 \\\\\frac{y_{D} +y_{D'} }{2} =2\\y_{D'} = 4 - y_{D} = 4 - (-1) = 4 + 1 = 5

4 0
3 years ago
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