Answer:
The solution of the system is the ordered pair (-13,-4)
Step-by-step explanation:
we have
-----> equation A
----> equation B
Solve the system by elimination
Multiply by 2 both sides equation B
----> equation C
Adds equation A and equation C

<em>Find the value of a</em>
substitute the value of b in any equation (i take equation B)



therefore
The solution of the system is the ordered pair (-13,-4)
Answer:
Numbers =(6,-2 )
Step-by step explanation:
Given
the sum of two numbers is four and the sum of their squares minus three times their product is 76,
Let the first term =X
Second term will be=4-x
So
X^2+(4-x)^2-3x(4-x)=76
x^2+16+x^2-8x-12x+3x^2=76
5x^2-20x+16=76
5x^2-20x-60=0
5(x^2-4x-12)=0
So x^2-4x-12=0
x^2-(6-2)x-12=0
x^2-6x+2x-12=0
X(x-6)+2(x-6)=0
(X-6)(X+2)=0
X=6,-2
Let X=6 and -2 then numbers will be 6 and (4-6)=-2
Hi! I'm pretty sure this is correct so here it goes:
A. 3/6
B. 12 4/6
Hello here is a solution :