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egoroff_w [7]
2 years ago
12

Stronitum-90 has a half-life of 29 years. if a site held 2000 kg of this isotope, approximately what mass of strontium-90 would

be left after 116 years?
Chemistry
2 answers:
4vir4ik [10]2 years ago
8 0
A half life of 29 years means that after 29 years, only half of this isotope would be left due to radioactive decay. If we start of with 2000g of it and leave it for 116 years, it would undergo 4 "half=lives". 116/29 = 4. So after the first half life, we would have 2000g/2 = 1000g left. After the second, we would have 500g left, after the third, 250g so after 4 half lives or 116 years, there would be 125 g  of Strontium-90 left at the site.
Pachacha [2.7K]2 years ago
7 0

given: stronitum-90

half-life: 29 years

total time: 116 years

original mass: 2000 kg

left: ?

116/29=4

0:2000

1:1000

2:500

3:250

4:125

THE ANSWER IS 125

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Explanation:

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What is calcium + chlorine when doing ionic bonds
vlabodo [156]
CaCl2
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6 0
3 years ago
A researcher wants to make a solution of agcl and water at 75 °c. for solid agcl at 75°c, ksp = 1.5 x 10-5.
mars1129 [50]
A.)
dG = -(0.008314)(348K) (1.5 * 10-5)
dG = -(0.008314)(348K (-11.107)
dG = 32 kJ/mol (rounded from 32.14) 
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B.)
AgCl(s) >>>> Ag+ and Cl-
<span>Ksp = {Ag+}{Cl-} 
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</span>1.5 * 10-5 = {X}{X}
<span>X2 = 1.5 x 10-5 
</span>X={Ag+}{Cl-}
Sol / AgCl = 3.873E-3 litres/moles
<span>(3.873E-3 moles AgCl/Litre) (143.32 g AgCl / mol)= 0.56g AgCl</span>
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3 years ago
Que microorganismo se han encontrado en el desierto
inysia [295]

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8 0
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Answer the following questions…
Zina [86]

The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.

<h3>What is pH?</h3>

pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.

As the solution contains 4.5 \times 10^{-3} \;\rm  M\; HCl the concentration of the hydronium ion will be the same, 4.5 \times 10^{-3} \;\rm  M.

The pH of the solution is calculated as:

\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}

The concentration of the hydroxide ion is calculated from pH and hydronium ion as:

\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}

Now, for the calcium hydroxide solution, the calculations are shown as,

\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-8)\\\\&= 10^{-8} \;\rm M\end{aligned}

pOH is calculated as:

\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &=  \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}

The concentration of calcium hydroxide is calculated as:

\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}

Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.

Learn more about pH and pOH here:

brainly.com/question/16062632

#SPJ1

3 0
2 years ago
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