Answer:
Explanation:
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In this case, for the given chemical reaction:
We can see a 4:2 mole ratio between lithium nitrate (68.946 g/mol) and lithium sulfate (109.94 g/mol); in such a way, via stoichiometry, the required mass of lithium nitrate to make 250 g of lithium sulfate turns out:
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Yes if it is released into calm water it can sink to the bottom and quickly spread the salty water that can kill organisms on the sea bed from a lack of oxygen.
Answer:
1.19 g
Explanation:
Given that:
Molecular weight of diene 136 g/mol
Molecular weight of Maleic Anhydride 96 g/mol
Mass of crude diene = 2.5 g
Percent of Composition for Peak A = 66%
Percent of Composition for Peak B = 22.66%
Percent of Composition for Peak C = 11.33%
Let us determine the amount of diene in the sample;
So, using to represent the amount of diene; we have :
=
=
= 1.65 g
Using the limiting reagent equation to determine the amount of Maleic Anhydride
=
=
= 1.19 g
The grams of Maleic Anhydride used to react with 2.5 g sample of crude diene = 1.19 g