Answer:
using only two types of seeds, both from the same source, repeating the experiment indoors under growth lights, and measuring plant height the same way and at the same time for both groups
Explanation:
Answer: 2.36 grams
Explanation: One molecule of NaCl has an atomic mass of 58.4 amu. That consists of one atom each of sodium (23 amu) and chlorine (35.4 amu).
Na 23 (23/58.4) = 0.3934
<u>Cl 35.4</u> (35.4/58.4) = 0.6066
58.4 amu
For Na: (6 grams)*(0.3934) = 2.36 grams
Answer:
4.5 × 10⁻⁹
Explanation:
Step 1: Write the reaction for the solution of CaCO₃
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Step 2: Convert the solubility of CaCO₃ from g/L to mol/L
We will use the following conversion factors:
- The molar mass of CaCO₃ is 100.09 g/mol.
- 1 L= 1000 mL.
- There are 0.00067 g of CaCO₃ per 100 mL of solution.
Step 3: Calculate the solubility product constant (Ksp)
To relate Ksp and the molar solubility (S), we need to make an ICE chart.
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant is:
Ksp = [Ca²⁺].[CO₃²⁻] = S² = (6.7 × 10⁻⁵)² = 4.5 × 10⁻⁹