Answer:
749 grams CO₂
Explanation:
To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.094 g/mol
1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O
Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)
Molar Mass (CO₂): 44.01 g/mol
250. g C₃H₈ 1 mole C₃H₈ 3 moles CO₂ 44.01 g
------------------ x ---------------------- x ---------------------- x -------------------- =
44.094 g 1 mole C₃H₈ 1 mole CO₂
= 749 grams CO₂
Answer:
b
Explanation:
it's b because I just went over that frome my class and got it correct
When heat energy at a constant pressure = the change of enthalpy
ΔH = Q
and when the internal energy of an ideal gas formula is:
ΔH = n.Cp.ΔT
and when Cp = (5/2) R at a constant pressure of a monatomic ideal gas
∴Q = n.(5/2).R.ΔT
∴ ΔT = Q / [n.(5/2).R]
when Q is the heat required = 43.08 J (given)
and n is no.of moles = mass / molar mass
= 1.1 g / 39.948 g/mol
= 0.0275 moles
and R is gas constant = 8.314472J/mol K
by substitution:
ΔT = 43.08 J / (0.0275moles *(5/2) * 8.314472 J/mol K
= 76.76 K
