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2 years ago

Why is it important to determine the qcalorimeter before determining the qmetal?

2 answers:

8 0

In order to determine the heat absorbed or given by a metal it is important to determine the heat loss or gained by calorimeter

If we dip a hot metal piece in a calorimeter, it will lose energy which will be absorbed by calorimeter

The heat absorbed by calorimeter = heat loss by metal

the heat absorbed by calorimeter = heat capacity of calorimter X change in temperature

so we should have the value of heat absorbed by calorimeter which will be equal to the heat loss by metal

heat loss by metal = mass of metal X specific heat of metal X change in temperature

thus we can calculate the specific heat of metal.

nataly862011 [7]2 years ago

7 0

<span>To find the enthalpy change per mole of a substance A in a reaction between two substances A and B, the substances are added to a calorimeter and the initial and final temperatures (before the reaction started and after it has finished) are noted</span>

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Did I get these correctly?

Luda [366]

Those are both correct! great job, keep up the good work (-:

4 0

2 years ago

If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?

padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, $t_{(1/2)}$ = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

$N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }$

For two half lives, t = 2 × $t_{(1/2)}$

∴ t = 2 × 15 = 30

$\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2$

$\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75$

∴ The amount left, N(t) = 0.75 grams

4 0

2 years ago

explain using diagrams how potassium forms the compound potassium flouride when it reacts with flourine

Katarina [22]

Answer:

The answer to your question is given below.

Explanation:

Potassium (K) has 19 electrons with electronic configuration of 2, 8, 8, 1.

Fluorine (F) has 9 electrons with electronic configuration of 2, 7.

Fluorine needs 1 electron to complete it's octet configuration.

Hence, potassium (K), will lose 1 electron to fluorine (F) to form potassium ion (K+) with electronic configuration of 2, 8, 8. The fluorine atom (F) will receive the 1 electron from potassium to form the fluoride ion (F-) with electronic configuration of 2, 8.

**** Please see attached photo for further details.

7 0

2 years ago

A small hole in the wing of a space shuttle requires a 20.7-cm² patch.

cricket20 [7]

The Patch's area of the space shuttle in km² is 2.07 × 10⁻⁹ km²

Given, that a space shuttle requires a 20.7 cm² patch

We have to convert the patch's area from cm² into km².

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

Patch area of the space shuttle is 20.7 cm²

1 cm = 0.00001 km

or, 1 cm² = (0.00001 km)²

or, 1 cm² = 10⁻¹⁰km²

20.7 cm² = 20.7 × 10⁻¹⁰km²

20.7 cm² = 2.07 × 10⁻⁹ km²

The patch area in square kilometers is 2.07 × 10⁻⁹ km²

To learn more about unit conversion, visit: brainly.com/question/11543684

#SPJ4

8 0

1 year ago

The melting point and freezing point of silver are 960 degrees celsius and 2162 degrees celsius, repectively. What is the freezi

Kay [80]

Answer: 960 degrees celsius

Explanation:

8 0

3 years ago