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ELEN [110]
3 years ago
5

1. Ramon puts two magnetic toy trains very close to each other on a track. What will happen next, and

Physics
2 answers:
nevsk [136]3 years ago
8 0
It depends what way they are facing.

If both the trains are north they will repel and same goes with the other way round.

Yet if you put one of them facing south and the other north then they will attract.


Hoped this helped!
FrozenT [24]3 years ago
5 0

Answer:

If one side of the train is positive and the other is negative they will attract if they are the same then they will repel.

Explanation:

If both are positive they will repel if both are negative they will repel and if they are opposites they will attract.

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A collision at 30 mph will take any loose object in your car and give it the same force as if it were:
Sauron [17]
The answer is “Thrown”
7 0
3 years ago
You observe two stars over the course of a year (or more) and find that both stars have measurable parallax. (1 arc second is 1/
Ierofanga [76]

Answer:

Star X is much closer since it is at a distance 1 parsec from the Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth. This angle is gotten when the position of the object is measured in January and then in July according to the configuration of the Earth with respect to the Sun in those months.

The distance between the Earth and the Sun is 150000000 Km. That distance is also known as an astronomical unit (1AU).

The parallax angle can be defined in the following way:

\tan{p} = \frac{1AU}{d}    

Where d is the distance to the star.

p('') = \frac{1}{d}    (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')} (2)

Equation (2) represents the distance in a unit known as parsec (pc).

Case of Star X (p('') = 1):

Using equation 2 the distance of star X can be known:

d(pc) = \frac{1}{1}

d(pc) = 1 pc

So, star X is at 1 parsec from Earth.

Case of Star Y (p('') = \frac{1}{2}):

d(pc) = \frac{1}{(\frac{1}{2})}

d(pc) = 2 pc

So, star Y is at 2 parsecs from the Earth.

Hence, star X is much closer.

Reminder:

Notice that in equation 2 the distance is inversely proportional to the parallax angle, so if the parallax angle decreases, the distance increases.

5 0
3 years ago
What average net force is required to accelerate a 9.5 g
Nesterboy [21]

Answer:

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

  = 650² ÷ 2(0.85)

  = 248,529.40 m/s²

But;

F = ma

   = 0.0095 kg × 248,529.40 m/s²

   = 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

6 0
3 years ago
Matter can exist in hw many states​
Mariulka [41]

Answer:

Matter can exist in four different states: solids, liquids, gases and plasma.

Explanation:

Hope this helps :)

4 0
3 years ago
Lightning flashed, and after 7 seconds there was a roll of thunder. To the nearest meter, determine how far lightning flashed fr
Nadya [2.5K]
Let’s come back to the equation of SPEED OF AN ECHO
SPEED =2XDISTANCE/ TIME
So 337*7/2=1179.5 nearest meter =1800 m away
Hope you will get it right
3 0
3 years ago
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