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Paul [167]
3 years ago
9

Describe how the law of conservation of energy is demonstrated in this laboratory activity.

Chemistry
1 answer:
Crank3 years ago
8 0
What laboratory activity. The law of conservation of energy is that energy remains constant. This relates to physics

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The element oxygen, represented by the symbol O, is classified as
Katarina [22]
Oxygen<span> is a </span>chemical element<span> having a symbol </span>O<span> and having an </span>atomic number<span> 8.
Oxygen is a pure substance , and it is not a mixture or solution, Niether it is a compound ... Instead , it forms chemical compounds by reacting with other elements.
So , according to above explanation ,
A. A pure substance , is the correct answer.</span>
3 0
3 years ago
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Which element is always found in impure form
Bezzdna [24]
C hydroyen
its aht plants breath

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3 years ago
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Which model of the atom is thought to be true?
FinnZ [79.3K]

Answer:

Hi the answer should be B or 2

Explanation:

Hope this helps!

6 0
2 years ago
What is symbol, molecule, electrovalent compound?​
jok3333 [9.3K]

Answer:

the abbreviation form of full name is called symbol.

the smallest unit of cimpound is called molecule.

8 0
3 years ago
How many moles are represented by 3.01 x10^24 oxygen atoms?
asambeis [7]
<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.<u> </u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})
  2. Multiply/Divide:                \displaystyle 4.99834 \ mol \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

4.99834 mol O₂ ≈ 5.00 mol O₂

4 0
3 years ago
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