All categories

2 years ago

Explain why in this crossing all of the hedgehog offspring are brown even though they all carry the white gene?

Chemistry

2 answers:

docker41 [41]2 years ago

7 0

They all have heterozygous Bb genes and brown is the dominant allele, and therefore all of the offspring are brown instead of white

Lina20 [59]2 years ago

4 0

Because The white gene is the recessive gene and the brown gene is the dominant gene hence all the offspring being brown instead of white :)

You might be interested in

Be sure to answer all parts. find the molar solubility of bacro4 (ksp= 2.1 × 10−10) in (a) pure water × 10 m (b) 1.6 × 10−3 m na

Vlad [161]

A) in pure water :

by using ICE table:

According to the reaction equation:

BaCrO4(s) → Ba^2+(aq) + CrO4^2-(aq)

initial 0 0

change +X +X

Equ X X

when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X* X

∴X = √2.1 x 10*-10

∴X = 1.4 x 10^-5

∴ the solubility = X = 1.4 X 10^-5

B) In 1.6 x 10^-3 m Na2CrO4

by using ICE table:

According to the reaction equation:

BaCrO4(s) → Ba^2+(aq) + CrO4^2-(aq)

initial 0 0.0016

Change +X +X

Equ X X+0.0016

when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X*(X+0.0016) by solving for X

∴ X = 1.3 x 10^-7

∴ solubility =X = 1.3 x 10^-7

3 0

2 years ago

What is true about all plutons? They form near Earth’s surface. They form below Earth’s surface. They cut across other rock laye

pishuonlain [190]

<u>Answer:</u> The correct answer is that they are formed below Earth's surface.

<u>Explanation:</u>

Plutons are defined as the intrusive igneous rocks named as plutonic rocks which are formed when the magma gets cools down slowly and solidifies below the Earth's surface.

It is different from volcanic rocks which are formed when lava gets cools down and solidifies on the Earth's surface.

Hence, the correct answer is that they are formed below Earth's surface.

7 0

2 years ago

Read 2 more answers

The pressure of a basketball is 412 mmHg. How many kPa is that equal to?

pychu [463]

Answer:

d. 54.9 kPa

Explanation:

mmHg and Pa are units of pressure used in chemistry principally in the study of gases. 1mmHg is equal to 133.322Pa. 412mmHg are:

412 mmHg * (133.322Pa / 1mmHg) = 54929 Pa

The prefix K (Kilo) represents one thousand of the determined unit.

54929Pa are:

54929Pa * (1KPa / 1000Pa) = 54.9kPa

Right answer is:

3 0

2 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

irinina [24]

Answer:

$m_{KBr}=6.030gKBr$

Explanation:

Hello.

In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:

$(T_b-T_b_0)=i*m*K_b$

Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:

$m=\frac{T_b-T_b_0}{i*K_b}=\frac{(119.3-117.8)\°C}{2*1.48\°C*kg*mol^{-1}}\\ \\m=0.507mol/kg$

Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:

$n_{KBr}=0.507mol/kg*0.1kg=0.0507mol$

Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:

$m_{KBr}=0.0507mol*\frac{119g}{1mol} \\\\m_{KBr}=6.030gKBr$

Best regards.

3 0

3 years ago

The heat required to raise the temperature of 12g of water from 16 C to 21 C is:

NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q=?
c= 4.186 $\frac{J}{g*C}$
m= 12 g
ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 $\frac{J}{g*C}$ *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

$cal=\frac{251.16 J * 0.2388 cal}{1 J}$

cal= 59.98 ≅ 60

<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>

3 0

2 years ago