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horrorfan [7]
3 years ago
8

Which equation best expresses the relationship between pressure and volume for gas?

Chemistry
2 answers:
pshichka [43]3 years ago
6 0
It won't be possible for me to answer this question if there is no context. I tried to find a similar question and I came up with one. The problem is shown in the attached picture. From the given choices, all their units are atm*mL. So, that means that P*V. The answer could only be (2) or (4). Let's try the data in the table to find out.

PV = (0.5 atm)(1000 mL) = 500 atm*mL
PV = (1 atm)(500 mL) = 500 atm*mL
PV = (2 atm)(250 mL) = 500 atm*mL
<em />
<em>Thus, the answer is choice (2).</em>

irina1246 [14]3 years ago
5 0

I think this is the question.

You might be interested in
The rate constant for the first-order decomposition at 45 °C of dinitrogen pentoxide, N2O5, dissolved in chloroform, CHCl3, is 6
weeeeeb [17]

Answer:

Rate of the reaction= 9.92× 10^-5 M² min-1

Explanation:

Using the equation of reaction

2N2O5 ⟶ 4NO2+O2

Rate = k[N2O5]²

From the question k= 6.2×10-4

[N2O5]= 0.4

Rate = 6.2×10-4[0.4]²= 9.92×10-5M² min-1

7 0
3 years ago
A silver cube with an edge length of 2.38 cm and a gold cube with an edge length of 2.79 cm are both heated to 81.9 ∘C and place
never [62]

Answer:

The final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

Explanation:

<u>Given data;</u>

edge length of silver, a = 2.38 cm = 0.0238 m

edge length of gold, a = 2.79 cm = 0.0279 m

final temperature of silver, t = 81.9 ° C

final temperature of Gold, t = 81.9 ° C

initial temperature of water, t = 19.6 ° C

volume of water, v =  109.5 mL = 0.0001095 m³

<u>Known data:</u>

density gold 19300 kg/m³

density silver 10490 kg/m³

density water 1000 kg/m³

specific heat gold is 129 J/kgC

specific heat silver is 240 J/kgC

specific heat water is 4200 J/kgC

<u>Calculated data</u>

Apply Pythagoras theorem to determine the side of each cube;

Silver cube;

let L be the side of the silver cube

Taking the cross section of the cube (form a right angled triangle), the edge  length forms the <em>hypotenuse side</em>.

L² + L² = 0.0238²

2L² = 0.0238²

L² = 0.0238² / 2

L² = 0.00028322

L = √0.00028322

L = 0.0168

Volume of cube = L³

Volume of the silver cube = (0.0168)³ = 4.742 x 10⁻⁶ m³

Gold cube;

let L be the side of the gold cube

L² + L² = 0.0279²

2L² = 0.0279²

L² = 0.0279² / 2

L² = 0.0003892

L = √0.0003892

L = 0.0197

Volume of cube = L³

Volume of the silver cube = (0.0197)³ = 7.645 x 10⁻⁶ m³

Mass of silver cube;

density = mass / volume

mass = density x volume

mass of silver cube = 10490 (kg/m³) x 4.742 x 10⁻⁶ (m³) = 0.0497 kg

Mass of Gold cube

mass of gold cube = 19300 (kg/m³) x 7.645 x 10⁻⁶ (m³) = 0.148 kg

Mass of water

mass of water = 1000 (kg/m³) x 0.0001095 (m³) = 0.1095 kg

Let the heat gained by cold water be  Q₁

Let the heat lost  by silver cube = Q₂

Let the heat lost  by gold cube = Q₃

Let the final temperature of water = T

Q₁  = 0.1095 kg x 4200 J/kgC x (T–19.6)

Q₂ = 0.0497 kg x 240 J/kgC x (81.9–T)

Q₃ = 0.148 kg x 129 J/kgC x (81.9–T)

At thermal equilibrium;

Q₁ = Q₂ + Q₃

0.1095 x 4200  (T–19.6)  = 0.0497 x 240 x (81.9–T)  + 0.148 x 129 x (81.9–T)

459.9 (T–19.6) = 11.928 (81.9–T) + 19.092(81.9–T)

459.9T - 9014.04 = 976.9032 - 11.928T + 1563.6348 - 19.092T

459.9T + 11.928T + 19.092T = 9014.04  + 976.9032 + 1563.6348

490.92T = 11554.578

T = 11554.578 / 490.92

T = 23.54 ⁰C

Therefore, the final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

6 0
3 years ago
Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?
Arlecino [84]

5.58 X 10^{-25} Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273  K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

number of moles = \frac{molecules}{Avagadro's number}

number of moles = 2.49 x 10^{-26}

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = \frac{nRT}{P}

putting the values in the rearranged equation:

V = \frac{2.49 X10^{-26}   X 0.08201 X 273}{1}

V = 5.58 X 10^{-25} Litres.

5 0
3 years ago
What kind of group 1 atoms are the most reactive? a. Small atoms c. Atoms with the most electrons in the valence level b. Large
garri49 [273]

Answer:

large atoms

Explanation:

its kinda obvious

4 0
3 years ago
Read 2 more answers
How much energy does it take to melt 2 kg of ice? (Refer to table of<br> constants for water.)
ioda
It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj


5 0
3 years ago
Read 2 more answers
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