Nucleotides consist offa phosphate group, a nitrogenous base, and a

If 252 grams of iron are reacted with 321 grams of chlorine gas, what is the mass of the excess reactant leftover after the reac

mario62 [17]

Answer:

Iron is in excess.

1) The mass of the iron remaining = 83.38 grams

2) Ethane is in excess. There will remain 90.06 grams ethane

Explanation:

Step 1: Data given

Mass of iron = 252 grams

Mass of Cl2 = 321 grams

Molar mass of Fe = 55.845

Molar mass of Cl2 = 70.9 g/mol

Step 2: The balanced equation

2Fe(s)+3Cl2(g)⟶2FeCl3(s)

Step 3: Calculate moles

Moles = mass / molar mass

Moles Fe = 252.0 grams / 55.845 g/mol = 4.512 moles

Moles Cl2 = 321.0 grams / 70.90 g/mol = 4.528 moles

Step 4: Calculate the limiting reactant

For 2 moles Fe we need 3 moles Cl2 to produce 2 moles Fecl3

Cl2 is the limiting reactant. It will completely be consumed (4.528 moles).

Fe is in excess. There will 4.528 * 2/3 = 3.019 moles be consumed

There will remain 4.512 - 3.019 = 1.493 moles of Fe

The mass of the iron remaining = 1.493 * 55.845 g/mol =83.38 grams

If 152 grams of ethane (C2H6) are reacted with 231 grams of oxygen gas, what is the excess reactant?

Step 1: Data given

Mass of ethane = 152.0 grams

mass of O2 =231.0 grams

Molar mass of ethane = 30.07 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

2C2H6(g) + 7O2(g) ⟶ 4CO2(g) + 6H2O(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles ethane = 152.0 grams / 30.07 g/mol = 5.055 moles

Moles O2 = 231.0 grams / 32.0 g/mol = 7.22 moles

Step 4: Calculate limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed (7.22 moles).

Ethane is in excess. There will react 7.22 * 2/7 = 2.06 moles

There will remain 5.055 - 2.06 = 2.995 moles ethane

2.995 moles ethane = 2.995 * 30.07 g/mol = 90.06 grams ethane

8 0

4 years ago

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Photodissociation of ozone (O3) can be described as producing an oxygen atom with heat of formation 247.5 kJ/mol. However, in re

Lapatulllka [165]

Answer:

0.2193 μm

Explanation:

The reaction showing the Photodissociation of ozone (O3) is given below as:

O₃ + hv --------------------------> O₂ + O⁺

H° (142.9) (0) (438kJ/mol).

The first thing to do here is to determine the change in the enthalpy of the total reaction, this can be done by subtracting the change in the enthalpy of the reactant from the change in enthalpy in the product. Hence, we have:

ΔH° = [438 kJ/mol + 247.5 kJ/mol] - (142.9) = 542.6 KJ/mol.

This value, that is 542.6 KJ/mol will then be used in the determination of the value for the maximum wavelength that could cause this photodissociation.

Therefore, the maximum wavelength could cause this photodissociation ≤ h × c/ E = [ 1.199 × 10⁻⁴]/ 542.6 = 2.193 × 10⁻⁷ = 0.2193 μm

7 0

3 years ago

An aqueous solution has a volume of 2.0 L and contains 36.0g of glucose. If the Molar Mass of glucose is 180g/mol, what is the m

choli [55]

Answer:

moles = 36/180 = 0.2 moles

molarity = 0.2/2 = 0.1 mol/dm3

3 0

3 years ago

Indicate the types of forces that are involved between the solute and solvent when forming a homogeneous solution between CH3CH2

Sliva [168]

Answer:

London dispersion forces

Explanation:

Intermolecular forces are the forces that facilitate interaction between solute and solvent molecules and thereby impact their solubility. These forces are broadly classified into four types arranged below from the strongest to the weakest:

1) Ionic > 2) Hydrogen bonding >3) Dipole-dipole >4) London dispersion

The hydrocarbons n-pentane $CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}$ and n--hexane $CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}CH_{3}$ are non-polar molecules. Therefore the only type of interaction that exists between them when forming a homogeneous solution are the weak london dispersion forces.

4 0

3 years ago

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The balanced equation below represents the reaction between a 5.0 gram sample of zinc metal and 0.5 M of hydrochloric acid. The

mezya [45]

Answer:

1) Increasing the concentration of HCl [HCl] will increase the reaction rate.

2) The potential energy diagram is shown in the attached image.

3) Because of it is an irreversible reaction that goes to the forward direction . The reaction takes place till HCl dissolves Zn completely.

Explanation:

Q1: State one change in reaction conditions, other than adding catalyst, that will increase the rate of the reaction.

The rate of the reaction, dissolving Zn in HCl, depends on the concentration of HCl.

Rate = k[HCl]².

Rate ∝ [HCl]².

The rate is directly proportional to the concentration of HCl raised to the power 2,

So, increasing the concentration of HCl [HCl] will increase the reaction rate.

Q2: Draw a potential energy diagram for this reaction.

Since the reaction releases energy that appears in the products side. So, the reaction is an exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

The potential energy diagram is shown in the attached image.

Q3: Explain why this reaction will not reach equilibrium.

Because of it is an irreversible reaction that goes to the forward direction . The reaction takes place till HCl dissolves Zn completely.

5 0

3 years ago