What is the formula for the perimeter of a semicircle

Mathematics

1 answer:

Rasek [7]2 years ago

8 0

Answer:

The perimeter of a semicircle is the sum of the half of the circumference of the circle and diameter. As the perimeter of a circle is 2πr or πd. So, the perimeter of a semicircle is 1/2 (πd) + d or πr + 2r, where r is the radius.

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Pls help me on this i don't know what to do

Katarina [22]

Answer:

$\text{A. The zeroes are 8 and -4, because }y=(x-8)(x+4)$

Step-by-step explanation:

$x^2-4x-32=0,\\(x-8)(x+4)=0,\\\begin{cases}x-8=0, x=\boxed{8},\\x+4=0, x=\boxed{-4}\end{cases}$

8 0

3 years ago

trasher [3.6K]

$\displaystyle\bf\\Explanations:\\\\The~similarity~ratio~of~two~similar~cones=k\\\\k=is~the~ratio~between~2~corresponding~lengths\\\\k=\frac{R_1}{R_2}=\frac{h_1}{h_2}\\\\The~ratio~between~2~corresponding~areas~of~similar~cones=k^2\\\\\frac{Area~1}{Area~2}=k^2\\\\The~ratio~between~the~volumes~of~the~2~similar~cones=k^3\\\\\frac{Volume~1}{Volume~2}=k^3$

$\displaystyle\bf\\Solving:\\\\Volume1=108~m^3\\\\Volume2=4m^3\\\\k^3=\frac{108}{4}\\\\k^3=27~~\Big|\sqrt{~}\\\\k=\sqrt[\b3]{27}\\\\k=3\\\\Area1=54~m^2\\\\\frac{Area~1}{Area~2}=k^2\\\\\frac{54}{Area~2}=3^2\\\\\frac{54}{Area~2}=9\\\\Area2=\frac{54}{9}\\\\\boxed{\bf Area2=6 m^2}$