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sertanlavr [38]
3 years ago
9

Beatrice threw a stone one and seven fourteenths yards. Tilly threw a stone nine fourteenths of a yard. What is a reasonable est

imate of the difference between their two throws?
1 yard
one and one half yards
2 yards
two and one half yards
Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

1 yard

Step-by-step explanation:

7/14 is 1/2 while 9/14 is greater than 1/2 but a lot less than a whole. So a strong estimate would assume that it is (1 1/2)-(1/2) for the approximate difference in  their throws were  

kaheart [24]3 years ago
6 0
The answer would be 1 yards because 1 and 7/14 minus 9/14 is 12/14 which rounds to 1 yard
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N is the sum of three consecutive primes and is also the product of two 2-digit primes, what is the least possible value of N
Nookie1986 [14]

Hello from MrBillDoesMath!

Answer:   N = 143

Discussion:

This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers:  11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of  3 consecutive primes.   I went back to my list of primes,  added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on  43, 47, and 53!

43 + 47 + 53 =  143 !


Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.


Thank you,

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Select the ordered pairs that satisfy the equation y=1/5x.Check all that apply.
vovikov84 [41]

Answer: C, E, F

Step-by-step explanation:

  1. Plug in the "x" and "y" values from the ordered pairs into the equation.
  2. For A: 3 = \frac{1(5)}{5} → 3 ≠ 1 → A is eliminated.
  3. For B: 5 = \frac{1(1)}{5} → 5 ≠ \frac{1}{5} → B is eliminated.
  4. For C: 2 = \frac{1(10)}{5} → 2 = 2 → C satisfies the equation.
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  6. For E: -1 = \frac{1(-5)}{5}→ -1 = -1 → E satisfies the equation.
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