First get everything to one side by adding 9 to 2x + 3 and you end up with 2x + 3 + 9 > 0 and you add 9 and 3 and it will be 2x + 12 > 0 and do the same for the second one but if your trying to solve for x, subtract the 3 on both sides and you will get 2x > -12 then you divide 2 by both sides and you get x which is
x > -6
Answer:
She spends 0.98 min, that is, aprroximately 1 min waiting at traffic lights.
Step-by-step explanation:
The length of the drive is 6 8/9 minutes
As a fraction, this is:
She spends 1/7 of this time waiting at traffic lights.
This is 1/7 of 62/9. So
Time waiting:
She spends 0.98 min, that is, aprroximately 1 min waiting at traffic lights.
Answer:
Δ QRS ≈ Δ QST ≈ Δ SRT ⇒ 3rd answer
Step-by-step explanation:
From the given figure
In Δ QRS
∵ m∠S = 90°
∵ m∠S = m∠QST + m∠RST
∴ m∠QST + m∠RST = 90° ⇒ (1)
- Use the fact the sum of the measures of the interior angles
of a Δ is 180°
∴ m∠Q + m∠S + m∠R = 180°
∵ m∠S = 90
∴ m∠Q + 90° + m∠R = 180°
- Subtract 90 from both sides
∴ m∠Q + m∠R = 90° ⇒ (2)
In Δ QST
∵ m∠QTS = 90°
- By using the fact above
∴ m∠Q + m∠QST = 90 ⇒ (3)
- From (1) and (3)
∴ m∠QST + m∠RST = m∠Q + m∠QST
- Subtract m∠QST from both sides
∴ m∠RST = m∠Q
In Δ SRT
∵ m∠STR = 90°
- By using the fact above
∴ m∠R + m∠RST = 90 ⇒ (4)
- From (1) and (4)
∴ m∠QST + m∠RST = m∠R + m∠RST
- Subtract m∠RST from both sides
∴ m∠QST = m∠R
In Δs QRS and QST
∵ m∠S = m∠QTS ⇒ right angles
∵ m∠R = m∠QST ⇒ proved
∵ ∠Q is a common angle in the two Δs
∴ Δ QRS ≈ Δ QST ⇒ AAA postulate of similarity
In Δs QRS and SRT
∵ m∠S = m∠STR ⇒ right angles
∵ m∠Q = m∠RST ⇒ proved
∵ ∠R is a common angle in the two Δs
∴ Δ QRS ≈ Δ SRT ⇒ AAA postulate of similarity
If two triangles are similar to one triangle, then the 3 triangles are similar
∵ Δ QRS ≈ Δ QST
∵ Δ QRS ≈ Δ SRT
∴ Δ QRS ≈ Δ QST ≈ Δ SRT
Answer:
f(-3)= 19
Step-by-step explanation:
you have to use substitution. Every time that you see an x, plug it in for a -3
f(x)= -5x+4
f(-3)= -5(-3)+4
f(-3)= 19
Answer:
∠1 = 107
∠2 = 73
Step-by-step explanation:
